CAIE P2 2023 November — Question 7 11 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2023
SessionNovember
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicImplicit equations and differentiation
TypeIterative method for special point
DifficultyChallenging +1.2 This question combines implicit differentiation (standard A-level technique) with an iterative method to find a coordinate. Part (a) requires setting dy/dx=0 and solving e^(2x)=18, which is straightforward. Parts (b)-(d) involve algebraic rearrangement and applying a given iterative formula—mechanical processes requiring care but no novel insight. The multi-step nature and iteration component elevate it slightly above average difficulty.
Spec1.07s Parametric and implicit differentiation1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

7 The curve with equation \(\mathrm { e } ^ { 2 x } - 18 x + y ^ { 3 } + y = 11\) has a stationary point at \(( p , q )\).
  1. Find the exact value of \(p\).
  2. Show that \(q = \sqrt [ 3 ] { 2 + 18 \ln 3 - q }\).
  3. Show by calculation that the value of \(q\) lies between 2.5 and 3.0.
  4. Use an iterative formula, based on the equation in (b), to find the value of \(q\) correct to 4 significant figures. Give the result of each iteration to 6 significant figures.
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

Question 7(a):
AnswerMarks Guidance
AnswerMark Guidance
Differentiate \(y^3\) to obtain \(3y^2\dfrac{dy}{dx}\)B1
Differentiate complete equation to produce at least one term involving \(\dfrac{dy}{dx}\) using implicit differentiationM1
Obtain \(2e^{2x} - 18 + 3y^2\dfrac{dy}{dx} + \dfrac{dy}{dx} = 0\)A1
Substitute \(\dfrac{dy}{dx}=0\) to obtain either \(p=\frac{1}{2}\ln 9\) or \(p=\ln 3\)A1
Total: 4
Question 7(b):
AnswerMarks Guidance
AnswerMark Guidance
Substitute value of \(p\) in original equation and rearrange as far as \(y^3=\ldots\) or \(q^3=\ldots\)M1 Allow in terms of \(\ln 9\)
Obtain given result \(q=\sqrt[3]{2+18\ln 3 - q}\) or \(y=\sqrt[3]{2+18\ln 3 - y}\) with sufficient detailA1 AG
Total: 2
Question 7(c):
AnswerMarks Guidance
AnswerMark Guidance
Consider sign of \(q - \sqrt[3]{2+18\ln 3 - q}\) or equivalent for \(2.5\) and \(3.0\)M1
Obtain \(-0.18...\) and \(0.34...\) with sufficient detail and justify conclusionA1 OE
Total: 2
Question 7(d):
AnswerMarks Guidance
AnswerMark Guidance
Use iteration process correctly at least onceM1
Obtain final answer \(q = 2.673\)A1 Answer required to exactly 4 s.f.
Show sufficient iterations to 6 sf to justify answer or show sign change in the interval \([2.6725, \ 2.6735]\)A1
Total3
## Question 7(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| Differentiate $y^3$ to obtain $3y^2\dfrac{dy}{dx}$ | B1 | |
| Differentiate complete equation to produce at least one term involving $\dfrac{dy}{dx}$ using implicit differentiation | M1 | |
| Obtain $2e^{2x} - 18 + 3y^2\dfrac{dy}{dx} + \dfrac{dy}{dx} = 0$ | A1 | |
| Substitute $\dfrac{dy}{dx}=0$ to obtain either $p=\frac{1}{2}\ln 9$ or $p=\ln 3$ | A1 | |
| **Total: 4** | | |

## Question 7(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Substitute value of $p$ in original equation and rearrange as far as $y^3=\ldots$ or $q^3=\ldots$ | M1 | Allow in terms of $\ln 9$ |
| Obtain given result $q=\sqrt[3]{2+18\ln 3 - q}$ or $y=\sqrt[3]{2+18\ln 3 - y}$ with sufficient detail | A1 | AG |
| **Total: 2** | | |

## Question 7(c):

| Answer | Mark | Guidance |
|--------|------|----------|
| Consider sign of $q - \sqrt[3]{2+18\ln 3 - q}$ or equivalent for $2.5$ and $3.0$ | M1 | |
| Obtain $-0.18...$ and $0.34...$ with sufficient detail and justify conclusion | A1 | OE |
| **Total: 2** | | |

## Question 7(d):

| Answer | Mark | Guidance |
|--------|------|----------|
| Use iteration process correctly at least once | **M1** | |
| Obtain final answer $q = 2.673$ | **A1** | Answer required to exactly 4 s.f. |
| Show sufficient iterations to 6 sf to justify answer or show sign change in the interval $[2.6725, \ 2.6735]$ | **A1** | |
| **Total** | **3** | |
7 The curve with equation $\mathrm { e } ^ { 2 x } - 18 x + y ^ { 3 } + y = 11$ has a stationary point at $( p , q )$.
\begin{enumerate}[label=(\alph*)]
\item Find the exact value of $p$.
\item Show that $q = \sqrt [ 3 ] { 2 + 18 \ln 3 - q }$.
\item Show by calculation that the value of $q$ lies between 2.5 and 3.0.
\item Use an iterative formula, based on the equation in (b), to find the value of $q$ correct to 4 significant figures. Give the result of each iteration to 6 significant figures.\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2023 Q7 [11]}}