OCR MEI C1 2007 June — Question 7 3 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Year2007
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSolving quadratics and applications
TypeSolving simple rational equations
DifficultyEasy -1.2 This is a straightforward algebraic manipulation question requiring students to clear the fraction by multiplying both sides by 2x, then rearrange to form and solve a linear equation (not actually quadratic). It's simpler than average A-level content, involving only basic algebraic skills with no problem-solving insight needed.
Spec1.02c Simultaneous equations: two variables by elimination and substitution

7 Solve the equation \(\frac { 4 x + 5 } { 2 x } = - 3\).

Question 7:
AnswerMarks Guidance
\(\frac{4x+5}{2x} = -3\)
\(4x + 5 = -6x\)M1 Multiply both sides by \(2x\)
\(10x = -5\)A1 Collect terms
\(x = -\frac{1}{2}\)A1 Correct answer
## Question 7:
$\frac{4x+5}{2x} = -3$ | |
$4x + 5 = -6x$ | M1 | Multiply both sides by $2x$
$10x = -5$ | A1 | Collect terms
$x = -\frac{1}{2}$ | A1 | Correct answer

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7 Solve the equation $\frac { 4 x + 5 } { 2 x } = - 3$.

\hfill \mbox{\textit{OCR MEI C1 2007 Q7 [3]}}