OCR MEI S1 — Question 4 6 marks

Exam BoardOCR MEI
ModuleS1 (Statistics 1)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConditional Probability
TypeIndependence test with conditional probability
DifficultyModerate -0.8 This is a straightforward application of basic conditional probability and independence definitions. Part (i) requires comparing P(L|R) with P(L), part (ii) uses the formula P(L∩R) = P(L|R)×P(R), and part (iii) is routine Venn diagram completion. All steps are direct recall of standard formulas with minimal calculation, making this easier than average.
Spec2.03a Mutually exclusive and independent events2.03b Probability diagrams: tree, Venn, sample space2.03c Conditional probability: using diagrams/tables2.03d Calculate conditional probability: from first principles

4 Each weekday, Marta travels to school by bus. Sometimes she arrives late.
  • \(L\) is the event that Marta arrives late.
  • \(R\) is the event that it is raining.
You are given that \(\mathrm { P } ( L ) = 0.15 , \mathrm { P } ( R ) = 0.22\) and \(\mathrm { P } ( L \mid R ) = 0.45\).
  1. Use this information to show that the events \(L\) and \(R\) are not independent.
  2. Find \(\mathrm { P } ( L \cap R )\).
  3. Draw a Venn diagram showing the events \(L\) and \(R\), and fill in the probability corresponding to each of the four regions of your diagram.

Question 4:
(i)
AnswerMarks Guidance
Because \(P(L \mid R) \neq P(L)\)E1 [1] Allow \(0.45 \neq 0.15\); Either \(P(L \cap R) = 0.099 \neq P(L) \times P(R)\); or \(0.099 \neq 0.15 \times 0.22 = 0.033\)
(ii)
AnswerMarks Guidance
\(P(L \cap R) = P(L \mid R) \times P(R) = 0.45 \times 0.22 = 0.099\)M1, A1 [2] For product; CAO; Allow \(\frac{99}{1000}\)
(iii)
AnswerMarks Guidance
Venn diagram with two intersecting circles labelled \(L\) and \(R\), showing values: 0.051, 0.099, 0.121, 0.729G1, G1, G1 [3] G1 for two labelled intersecting circles; G1 for at least 2 correct probabilities, FT their \(P(L \cap R)\) from (ii) provided \(\leq 0.15\); G1 for remaining probabilities, FT their \(P(L \cap R)\) providing probabilities between 0 and 1
## Question 4:

**(i)**
Because $P(L \mid R) \neq P(L)$ | E1 [1] | Allow $0.45 \neq 0.15$; Either $P(L \cap R) = 0.099 \neq P(L) \times P(R)$; or $0.099 \neq 0.15 \times 0.22 = 0.033$

**(ii)**
$P(L \cap R) = P(L \mid R) \times P(R) = 0.45 \times 0.22 = 0.099$ | M1, A1 [2] | For product; CAO; Allow $\frac{99}{1000}$

**(iii)**
Venn diagram with two intersecting circles labelled $L$ and $R$, showing values: 0.051, 0.099, 0.121, 0.729 | G1, G1, G1 [3] | G1 for two labelled intersecting circles; G1 for at least 2 correct probabilities, FT their $P(L \cap R)$ from (ii) provided $\leq 0.15$; G1 for remaining probabilities, FT their $P(L \cap R)$ providing probabilities between 0 and 1

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4 Each weekday, Marta travels to school by bus. Sometimes she arrives late.

\begin{itemize}
  \item $L$ is the event that Marta arrives late.
  \item $R$ is the event that it is raining.
\end{itemize}

You are given that $\mathrm { P } ( L ) = 0.15 , \mathrm { P } ( R ) = 0.22$ and $\mathrm { P } ( L \mid R ) = 0.45$.\\
(i) Use this information to show that the events $L$ and $R$ are not independent.\\
(ii) Find $\mathrm { P } ( L \cap R )$.\\
(iii) Draw a Venn diagram showing the events $L$ and $R$, and fill in the probability corresponding to each of the four regions of your diagram.

\hfill \mbox{\textit{OCR MEI S1  Q4 [6]}}