CAIE P2 2022 June — Question 3 7 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2022
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeDefinite integral with trigonometric functions
DifficultyStandard +0.3 This is a straightforward two-part question requiring (a) solving 3sin(x) - 3sin(2x) = 0 using the double angle formula, and (b) integrating standard trigonometric functions over a given interval. Both parts use routine A-level techniques with no novel problem-solving required, making it slightly easier than average.
Spec1.05l Double angle formulae: and compound angle formulae1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)1.08e Area between curve and x-axis: using definite integrals

3 \includegraphics[max width=\textwidth, alt={}, center]{ed12a4fb-e3bf-4d00-ad09-9ba5be941dd5-04_531_739_258_703} The diagram shows the curve with equation \(y = 3 \sin x - 3 \sin 2 x\) for \(0 \leqslant x \leqslant \pi\). The curve meets the \(x\)-axis at the origin and at the points with \(x\)-coordinates \(a\) and \(\pi\).
  1. Find the exact value of \(a\).
  2. Find the area of the shaded region.

Question 3(a):
AnswerMarks Guidance
AnswerMarks Guidance
Attempt to find \(x\)-value from \(3\sin x - 3\sin 2x = 0\) using identity for \(\sin 2x\)M1
Obtain at least \(\cos x = \frac{1}{2}\)A1
Obtain \(\frac{1}{3}\pi\)A1 SC B3 can be spotted from \(\sin x = \sin 2x\)
Question 3(b):
AnswerMarks Guidance
AnswerMarks Guidance
Integrate to obtain form \(k_1\cos x + k_2\cos 2x\)\*M1 non-zero constants \(k_1\), \(k_2\); M0 for \(3\cos x \pm 6\cos 2x\)
Obtain correct \(-3\cos x + \frac{3}{2}\cos 2x\)A1
Attempt value of integral using their lower limit (in radians) and \(\pi\) correctlyDM1 Allow one sign error
Obtain \(\frac{27}{4}\)A1 OE
## Question 3(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Attempt to find $x$-value from $3\sin x - 3\sin 2x = 0$ using identity for $\sin 2x$ | M1 | |
| Obtain at least $\cos x = \frac{1}{2}$ | A1 | |
| Obtain $\frac{1}{3}\pi$ | A1 | **SC B3** can be spotted from $\sin x = \sin 2x$ |

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## Question 3(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Integrate to obtain form $k_1\cos x + k_2\cos 2x$ | \*M1 | non-zero constants $k_1$, $k_2$; M0 for $3\cos x \pm 6\cos 2x$ |
| Obtain correct $-3\cos x + \frac{3}{2}\cos 2x$ | A1 | |
| Attempt value of integral using their lower limit (in radians) and $\pi$ correctly | DM1 | Allow one sign error |
| Obtain $\frac{27}{4}$ | A1 | OE |

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3\\
\includegraphics[max width=\textwidth, alt={}, center]{ed12a4fb-e3bf-4d00-ad09-9ba5be941dd5-04_531_739_258_703}

The diagram shows the curve with equation $y = 3 \sin x - 3 \sin 2 x$ for $0 \leqslant x \leqslant \pi$. The curve meets the $x$-axis at the origin and at the points with $x$-coordinates $a$ and $\pi$.
\begin{enumerate}[label=(\alph*)]
\item Find the exact value of $a$.
\item Find the area of the shaded region.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2022 Q3 [7]}}