OCR S1 2007 June — Question 7 9 marks

Exam BoardOCR
ModuleS1 (Statistics 1)
Year2007
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Distribution
TypeVerify conditions in context
DifficultyModerate -0.3 This is a straightforward binomial distribution question requiring recall of conditions (part i), direct use of cumulative probability tables (part ii), and simple complement/conditional probability calculations (parts iii-iv). All parts follow standard S1 patterns with no novel problem-solving required, making it slightly easier than average.
Spec2.04b Binomial distribution: as model B(n,p)2.04c Calculate binomial probabilities

7 On average, \(25 \%\) of the packets of a certain kind of soup contain a voucher. Kim buys one packet of soup each week for 12 weeks. The number of vouchers she obtains is denoted by X .
  1. State two conditions needed for X to be modelled by the distribution \(\mathrm { B } ( 12,0.25 )\). In the rest of this question you should assume that these conditions are satisfied.
  2. Find \(\mathrm { P } ( \mathrm { X } \leqslant 6 )\). In order to claim a free gift, 7 vouchers are needed.
  3. Find the probability that Kim will be able to claim a free gift at some time during the 12 weeks.
  4. Find the probability that Kim will be able to claim a free gift in the 12th week but not before.

Part i
\(P(\)contains voucher\()\) constant oe
AnswerMarks Guidance
Packets indep oeB1 Context essential
B12 NOT vouchers indep
Part ii
AnswerMarks Guidance
0.9857 or 0.986 (3 sfs)B2 2
or for 7 terms correct, allow one omit or
extra
NOT \(1 - 0.9857 = 0.0143\) (see (iii))
Part iii
AnswerMarks Guidance
\((1 - 0.9857) = 0.014(3)\) (2 sfs)B1ft Allow 1- their (ii) correctly calc'd
1
Part iv
\(B(11, 0.25)\) or 6 in 11 wks stated or impl
\(^{11}C_6 × 0.75^5 × 0.25^6\) (= 0.0267663)
AnswerMarks Guidance
\(P(6 \text{ from } 11) × 0.25 = 0.00669\) or \(6.69 × 10^{-3}\) (3 sfs)B1 or \(0.75^5 × 0.25^6\) (\(a + b = 11\)) or \(^{11}C_6\)
M1dep B1
M1
A14
Total: 9
### Part i
$P($contains voucher$)$ constant oe
Packets indep oe | B1 | Context essential
| B1 | 2 | NOT vouchers indep

### Part ii
0.9857 or 0.986 (3 sfs) | B2 | 2 | B1 for 0.9456 or 0.946 or 0.997(2)
| | or for 7 terms correct, allow one omit or
| | extra
| | NOT $1 - 0.9857 = 0.0143$ (see (iii))

### Part iii
$(1 - 0.9857) = 0.014(3)$ (2 sfs) | B1ft | Allow 1- their (ii) correctly calc'd
| 1 |

### Part iv
$B(11, 0.25)$ or 6 in 11 wks stated or impl
$^{11}C_6 × 0.75^5 × 0.25^6$ (= 0.0267663)
$P(6 \text{ from } 11) × 0.25 = 0.00669$ or $6.69 × 10^{-3}$ (3 sfs) | B1 | or $0.75^5 × 0.25^6$ ($a + b = 11$) or $^{11}C_6$
| M1 | dep B1
| M1 |
| A1 | 4

**Total: 9**

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7 On average, $25 \%$ of the packets of a certain kind of soup contain a voucher. Kim buys one packet of soup each week for 12 weeks. The number of vouchers she obtains is denoted by X .\\
(i) State two conditions needed for X to be modelled by the distribution $\mathrm { B } ( 12,0.25 )$.

In the rest of this question you should assume that these conditions are satisfied.\\
(ii) Find $\mathrm { P } ( \mathrm { X } \leqslant 6 )$.

In order to claim a free gift, 7 vouchers are needed.\\
(iii) Find the probability that Kim will be able to claim a free gift at some time during the 12 weeks.\\
(iv) Find the probability that Kim will be able to claim a free gift in the 12th week but not before.

\hfill \mbox{\textit{OCR S1 2007 Q7 [9]}}