| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2008 |
| Session | January |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | SUVAT in 2D & Gravity |
| Type | Free fall: time or distance |
| Difficulty | Moderate -0.8 This is a straightforward two-stage SUVAT problem with standard bookwork calculations. Part (a) uses s=ut+½at² with u=0, part (b) uses v=u+at, and part (c) requires applying SUVAT again for the free-fall phase. All steps are routine applications of memorized formulae with no problem-solving insight required, making it easier than average but not trivial due to the two-stage nature. |
| Spec | 3.02a Kinematics language: position, displacement, velocity, acceleration3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form |
| Answer | Marks | Guidance |
|---|---|---|
| Working | Marks | Notes |
| \(27 = 0 + \frac{1}{2}a \cdot 3^2 \Rightarrow a = 6\) | M1 A1 (2) |
| Answer | Marks | Guidance |
|---|---|---|
| Working | Marks | Notes |
| \(v = 6 \times 3 = 18 \text{ ms}^{-1}\) | M1 A1 f.t. (2) |
| Answer | Marks | Guidance |
|---|---|---|
| Working | Marks | Notes |
| From \(t=3\) to \(t=5\): \(s = 18 \times 2 - \frac{1}{2} \times 9.8 \times 2^2\) | M1 A1 f.t. | |
| Total ht. \(= s + 27 = 43.4\text{ m},\ 43\text{ m}\) | M1 A1 (4) | Total: 8 |
## Question 2:
### Part (a)
| Working | Marks | Notes |
|---------|-------|-------|
| $27 = 0 + \frac{1}{2}a \cdot 3^2 \Rightarrow a = 6$ | M1 A1 (2) | |
### Part (b)
| Working | Marks | Notes |
|---------|-------|-------|
| $v = 6 \times 3 = 18 \text{ ms}^{-1}$ | M1 A1 f.t. (2) | |
### Part (c)
| Working | Marks | Notes |
|---------|-------|-------|
| From $t=3$ to $t=5$: $s = 18 \times 2 - \frac{1}{2} \times 9.8 \times 2^2$ | M1 A1 f.t. | |
| Total ht. $= s + 27 = 43.4\text{ m},\ 43\text{ m}$ | M1 A1 (4) | **Total: 8** |
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2. A firework rocket starts from rest at ground level and moves vertically. In the first 3 s of its motion, the rocket rises 27 m . The rocket is modelled as a particle moving with constant acceleration $a \mathrm {~m} \mathrm {~s} ^ { - 2 }$. Find
\begin{enumerate}[label=(\alph*)]
\item the value of $a$,
\item the speed of the rocket 3 s after it has left the ground.
After 3 s , the rocket burns out. The motion of the rocket is now modelled as that of a particle moving freely under gravity.
\item Find the height of the rocket above the ground 5 s after it has left the ground.
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2008 Q2 [8]}}