Edexcel M1 2015 June — Question 2 9 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2015
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeCollision with two possible outcomes
DifficultyStandard +0.3 This is a straightforward M1 collision problem requiring conservation of momentum and impulse calculation. Part (a) involves algebraic manipulation to find k, and part (b) is direct application of impulse = change in momentum. The 'show that' structure and clear setup make this slightly easier than average, though it requires careful sign conventions.
Spec6.03b Conservation of momentum: 1D two particles6.03e Impulse: by a force

2. Particle \(A\) of mass \(2 m\) and particle \(B\) of mass \(k m\), where \(k\) is a positive constant, are moving towards each other in opposite directions along the same straight line on a smooth horizontal plane. The particles collide directly. Immediately before the collision the speed of \(A\) is \(u\) and the speed of \(B\) is \(3 u\). The direction of motion of each particle is reversed by the collision. Immediately after the collision the speed of \(A\) is \(\frac { 1 } { 2 } u\).
  1. Show that \(k < 1\)
  2. Find, in terms of \(m\) and \(u\), the magnitude of the impulse exerted on \(B\) by \(A\) in the collision.

Question 2(a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance Notes
\(2mu - km3u = -2m\frac{1}{2}u + kmv\)M1 Conservation of momentum. Must have all four terms but condone sign errors and consistent omission of \(m\) or \(g\) included in all terms
\((3u = kv + 3ku)\)A2,1,0 \(-1\) for each error. All correct A1A1, one error A1A0, two or more errors A0A0
\(v=(1-k)\dfrac{3u}{k}\) or \(k=\dfrac{3u}{v+3u}\)A1 Correct expression for \(v\) or for \(kv\) or for \(k\)
\(v > 0 \Rightarrow\)M1 Correct inequality for their \(v\)
\(\Rightarrow k < 1\)A1 Reach given answer correctly
Total: (6)
Question 2(b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance Notes
\(I = 2m(\frac{1}{2}u - {-u})\)M1 Impulse \(=\) change in momentum for \(A\) or for \(B\). Condone sign errors
A1Correct unsimplified expression in terms of \(m\) and \(u\). Allow \(+/-\)
\(= 3mu\)A1 Correct answer only
Total: (3)
# Question 2(a):

| Answer/Working | Marks | Guidance Notes |
|---|---|---|
| $2mu - km3u = -2m\frac{1}{2}u + kmv$ | M1 | Conservation of momentum. Must have all four terms but condone sign errors and consistent omission of $m$ or $g$ included in all terms |
| $(3u = kv + 3ku)$ | A2,1,0 | $-1$ for each error. All correct A1A1, one error A1A0, two or more errors A0A0 |
| $v=(1-k)\dfrac{3u}{k}$ or $k=\dfrac{3u}{v+3u}$ | A1 | Correct expression for $v$ or for $kv$ or for $k$ |
| $v > 0 \Rightarrow$ | M1 | Correct inequality for their $v$ |
| $\Rightarrow k < 1$ | A1 | Reach **given answer** correctly |
| **Total: (6)** | | |

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# Question 2(b):

| Answer/Working | Marks | Guidance Notes |
|---|---|---|
| $I = 2m(\frac{1}{2}u - {-u})$ | M1 | Impulse $=$ change in momentum for $A$ or for $B$. Condone sign errors |
| | A1 | Correct unsimplified expression in terms of $m$ and $u$. Allow $+/-$ |
| $= 3mu$ | A1 | Correct answer only |
| **Total: (3)** | | |

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2. Particle $A$ of mass $2 m$ and particle $B$ of mass $k m$, where $k$ is a positive constant, are moving towards each other in opposite directions along the same straight line on a smooth horizontal plane. The particles collide directly. Immediately before the collision the speed of $A$ is $u$ and the speed of $B$ is $3 u$. The direction of motion of each particle is reversed by the collision. Immediately after the collision the speed of $A$ is $\frac { 1 } { 2 } u$.
\begin{enumerate}[label=(\alph*)]
\item Show that $k < 1$
\item Find, in terms of $m$ and $u$, the magnitude of the impulse exerted on $B$ by $A$ in the collision.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1 2015 Q2 [9]}}