Edexcel M1 2021 January — Question 4 6 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2021
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeNon-uniform beam on supports
DifficultyStandard +0.3 This is a standard M1 moments problem with two equilibrium conditions. Students must set up moments equations about two different pivot points (D and C) using the 'about to tilt' condition (reaction force = 0 at the other support). The algebra is straightforward: two equations, two unknowns (W and x). While it requires understanding of the tilting concept, this is a textbook application of moments with no novel insight needed, making it slightly easier than average.
Spec3.04a Calculate moments: about a point3.04b Equilibrium: zero resultant moment and force

4. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{ca445c1e-078c-4a57-94df-de90f30f8efd-08_426_1428_118_258} \captionsetup{labelformat=empty} \caption{Figure 2}
\end{figure} \begin{verbatim} A metal girder \(A B\) has weight \(W\) newtons and length 6 m . The girder rests in a horizontal position on two supports \(C\) and \(D\) where \(A C = D B = 1 \mathrm {~m}\), as shown in Figure 2. When a force of magnitude 900 N is applied vertically upwards to the girder at \(A\), the girder is about to tilt about \(D\). When a force of magnitude 1500 N is applied vertically upwards to the girder at \(B\), the girder is about to tilt about \(C\). The girder is modelled as a non-uniform rod whose centre of mass is a distance \(x\) metres from \(A\). Find the value of \(x\). A metal girder AB has weight When a force of magnitude 1500 N is applied vertically upwards to the girder at \(B\), the girder is about to tilt about \(C\). The girder is modelled as a non-uniform rod whose centre of mass is a distance \(x\) metres from \(A\). Find the value of \(x\). \end{verbatim}

Question 4:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(M(D),\ 900 \times 5 = W(5-x)\)M1A1 Equation in \(W\) and one unknown length, dim correct, condone sign errors. Extra \(g\) on one side is A error. M0 if \(R_C = 0\) never set. Allow consistent use of \(Mg\) for \(W\)
\(M(C),\ 1500 \times 5 = W(x-1)\)M1A1 Equation in \(W\) and same unknown length, dim correct, condone sign errors. Extra \(g\) on one side is A error. M0 if \(R_D = 0\) never set
Solving for \(x\)DM1 Dependent on two previous M marks
\(x = 3.5\)A1 cao, no wrong working seen
# Question 4:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $M(D),\ 900 \times 5 = W(5-x)$ | M1A1 | Equation in $W$ and one unknown length, dim correct, condone sign errors. Extra $g$ on one side is A error. M0 if $R_C = 0$ never set. Allow consistent use of $Mg$ for $W$ |
| $M(C),\ 1500 \times 5 = W(x-1)$ | M1A1 | Equation in $W$ and same unknown length, dim correct, condone sign errors. Extra $g$ on one side is A error. M0 if $R_D = 0$ never set |
| Solving for $x$ | DM1 | Dependent on two previous M marks |
| $x = 3.5$ | A1 | cao, no wrong working seen |

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4.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{ca445c1e-078c-4a57-94df-de90f30f8efd-08_426_1428_118_258}
\captionsetup{labelformat=empty}
\caption{Figure 2}
\end{center}
\end{figure}

\begin{verbatim}
A metal girder $A B$ has weight $W$ newtons and length 6 m . The girder rests in a horizontal position on two supports $C$ and $D$ where $A C = D B = 1 \mathrm {~m}$, as shown in Figure 2.
When a force of magnitude 900 N is applied vertically upwards to the girder at $A$, the girder is about to tilt about $D$.
When a force of magnitude 1500 N is applied vertically upwards to the girder at $B$, the girder is about to tilt about $C$.
The girder is modelled as a non-uniform rod whose centre of mass is a distance $x$ metres from $A$.
Find the value of $x$.
A metal girder AB has weight 
When a force of magnitude 1500 N is applied vertically upwards to the girder at $B$, the girder is about to tilt about $C$.
The girder is modelled as a non-uniform rod whose centre of mass is a distance $x$ metres from $A$. Find the value of $x$.
\end{verbatim}

\hfill \mbox{\textit{Edexcel M1 2021 Q4 [6]}}