CAIE P1 2019 November — Question 8 8 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2019
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRadians, Arc Length and Sector Area
TypeTangent and sector - two tangents from external point
DifficultyStandard +0.3 This is a straightforward application of arc length formula (s = rθ) to find the radius, followed by standard tangent-from-external-point geometry and sector area formulas. All steps are routine with no novel insight required, making it slightly easier than average.
Spec1.03f Circle properties: angles, chords, tangents1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

8 \includegraphics[max width=\textwidth, alt={}, center]{0e4a249a-9e6a-49d4-996c-fe07b7730f59-12_560_574_258_781} The diagram shows a sector \(O A C\) of a circle with centre \(O\). Tangents \(A B\) and \(C B\) to the circle meet at \(B\). The arc \(A C\) is of length 6 cm and angle \(A O C = \frac { 3 } { 8 } \pi\) radians.
  1. Find the length of \(O A\) correct to 4 significant figures.
  2. Find the perimeter of the shaded region.
  3. Find the area of the shaded region.

Question 8(i):
AnswerMarks Guidance
AnswerMarks Guidance
\(OA \times \frac{3}{8}\pi = 6\)M1
\(OA = \frac{16}{\pi} = 5.093(0)\)A1
Question 8(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(AB = their\ 5.0930 \times \tan\frac{3}{16}\pi\)M1
Perimeter \(= 2\times 3.4030 + 6 = 12.8\)A1
Question 8(iii):
AnswerMarks Guidance
AnswerMarks Guidance
Area \(OABC = (2\times\frac{1}{2})\times their\ 5.0930 \times their\ 3.4030\)M1
Area sector \(= \frac{1}{2}\times(their\ 5.0930)^2\times\frac{3}{8}\pi\)M1
Shaded area \(= their\ 17.331 - their\ 15.279 = 2.05\)M1A1
## Question 8(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $OA \times \frac{3}{8}\pi = 6$ | M1 | |
| $OA = \frac{16}{\pi} = 5.093(0)$ | A1 | |

## Question 8(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $AB = their\ 5.0930 \times \tan\frac{3}{16}\pi$ | M1 | |
| Perimeter $= 2\times 3.4030 + 6 = 12.8$ | A1 | |

## Question 8(iii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Area $OABC = (2\times\frac{1}{2})\times their\ 5.0930 \times their\ 3.4030$ | M1 | |
| Area sector $= \frac{1}{2}\times(their\ 5.0930)^2\times\frac{3}{8}\pi$ | M1 | |
| Shaded area $= their\ 17.331 - their\ 15.279 = 2.05$ | M1A1 | |
8\\
\includegraphics[max width=\textwidth, alt={}, center]{0e4a249a-9e6a-49d4-996c-fe07b7730f59-12_560_574_258_781}

The diagram shows a sector $O A C$ of a circle with centre $O$. Tangents $A B$ and $C B$ to the circle meet at $B$. The arc $A C$ is of length 6 cm and angle $A O C = \frac { 3 } { 8 } \pi$ radians.\\
(i) Find the length of $O A$ correct to 4 significant figures.\\

(ii) Find the perimeter of the shaded region.\\

(iii) Find the area of the shaded region.\\

\hfill \mbox{\textit{CAIE P1 2019 Q8 [8]}}