Edexcel F3 2020 June — Question 4 9 marks

Exam BoardEdexcel
ModuleF3 (Further Pure Mathematics 3)
Year2020
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration by Parts
TypeReduction formula or recurrence
DifficultyChallenging +1.2 This is a standard Further Maths reduction formula question requiring two applications of integration by parts to derive the recurrence relation, then systematic application to find a specific integral. While it requires careful algebraic manipulation and multiple steps, the technique is routine for F3 students and follows a well-practiced pattern with no novel insight needed.
Spec1.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.08i Integration by parts8.06a Reduction formulae: establish, use, and evaluate recursively

4.
  1. Show that, for \(n \geqslant 2\)
  2. Hence find the functions \(\mathrm { f } ( x )\) and \(\mathrm { g } ( x )\) such that $$\int x ^ { 4 } \cos x \mathrm {~d} x = \mathrm { f } ( x ) \sin x + \mathrm { g } ( x ) \cos x + c$$ where \(c\) is an arbitrary constant. $$I _ { n } = \int x ^ { n } \cos x \mathrm {~d} x$$
    1. Show that, for \(n \geqslant 2\) $$I _ { n } = x ^ { n } \sin x + n x ^ { n - 1 } \cos x - n ( n - 1 ) I _ { n - 2 }$$
    2. Hence find the functions \(\mathrm { f } ( x )\) and \(\mathrm { g } ( x )\) such that

Question 4:
\[I_n = \int x^n \cos x\, dx\]
Part (a):
AnswerMarks Guidance
Working/AnswerMark Notes
\(\int x^n\cos x\,dx = x^n\sin x - \int nx^{n-1}\sin x\,dx\)M1A1 M1: Parts in the correct direction; A1: Correct expression
\(= x^n\sin x - \left\{-nx^{n-1}\cos x + \int n(n-1)x^{n-2}\cos x\,dx\right\}\)dM1 Uses integration by parts again (dependent on first M)
\(= x^n\sin x + nx^{n-1}\cos x - n(n-1)I_{n-2}\)A1* Fully correct proof with no errors
Alternative:
AnswerMarks Guidance
Working/AnswerMark Notes
\(I_n = \int x^{n-1}(x\cos x)\,dx = x^n\sin x + x^{n-1}\cos x - (n-1)\int x^{n-2}(x\sin x+\cos x)\,dx\)M1A1 M1: Parts in correct direction; A1: Correct expression
\(= x^n\sin x + x^{n-1}\cos x - (n-1)\left\{-x^{n-1}\cos x + (n-1)I_{n-2}\right\} - (n-1)I_{n-2}\)dM1 Uses integration by parts again (dependent on first M)
\(= x^n\sin x + nx^{n-1}\cos x - n(n-1)I_{n-2}\)A1* Fully correct proof with no errors
Part (b):
AnswerMarks Guidance
Working/AnswerMark Notes
\(I_0 = \sin x\ (+k)\)B1
\(I_4 = x^4\sin x + 4x^3\cos x - 12I_2\)M1 Applies reduction formula once for \(I_4\) or \(I_2\)
\(= x^4\sin x + 4x^3\cos x - 12\left(x^2\sin x + 2x\cos x - 2I_0\right)\)M1 Applies reduction formula again and obtains expression for \(I_4\) which can include \(I_0\) but not \(I_2\)
\(= (x^4-12x^2+24)\sin x + (4x^3-24x)\cos x + c\)A1A1 Award A1 for either bracket and A1 for the other. If answer is not factorised but otherwise correct, award A1A0
# Question 4:

$$I_n = \int x^n \cos x\, dx$$

## Part (a):

| Working/Answer | Mark | Notes |
|---|---|---|
| $\int x^n\cos x\,dx = x^n\sin x - \int nx^{n-1}\sin x\,dx$ | M1A1 | M1: Parts in the correct direction; A1: Correct expression |
| $= x^n\sin x - \left\{-nx^{n-1}\cos x + \int n(n-1)x^{n-2}\cos x\,dx\right\}$ | dM1 | Uses integration by parts again (dependent on first M) |
| $= x^n\sin x + nx^{n-1}\cos x - n(n-1)I_{n-2}$ | A1* | Fully correct proof with no errors |

### Alternative:

| Working/Answer | Mark | Notes |
|---|---|---|
| $I_n = \int x^{n-1}(x\cos x)\,dx = x^n\sin x + x^{n-1}\cos x - (n-1)\int x^{n-2}(x\sin x+\cos x)\,dx$ | M1A1 | M1: Parts in correct direction; A1: Correct expression |
| $= x^n\sin x + x^{n-1}\cos x - (n-1)\left\{-x^{n-1}\cos x + (n-1)I_{n-2}\right\} - (n-1)I_{n-2}$ | dM1 | Uses integration by parts again (dependent on first M) |
| $= x^n\sin x + nx^{n-1}\cos x - n(n-1)I_{n-2}$ | A1* | Fully correct proof with no errors |

## Part (b):

| Working/Answer | Mark | Notes |
|---|---|---|
| $I_0 = \sin x\ (+k)$ | B1 | |
| $I_4 = x^4\sin x + 4x^3\cos x - 12I_2$ | M1 | Applies reduction formula once for $I_4$ or $I_2$ |
| $= x^4\sin x + 4x^3\cos x - 12\left(x^2\sin x + 2x\cos x - 2I_0\right)$ | M1 | Applies reduction formula again and obtains expression for $I_4$ which can include $I_0$ but not $I_2$ |
| $= (x^4-12x^2+24)\sin x + (4x^3-24x)\cos x + c$ | A1A1 | Award A1 for either bracket and A1 for the other. If answer is not factorised but otherwise correct, award A1A0 |

---
4.
\begin{enumerate}[label=(\alph*)]
\item Show that, for $n \geqslant 2$
\item Hence find the functions $\mathrm { f } ( x )$ and $\mathrm { g } ( x )$ such that

$$\int x ^ { 4 } \cos x \mathrm {~d} x = \mathrm { f } ( x ) \sin x + \mathrm { g } ( x ) \cos x + c$$

where $c$ is an arbitrary constant.

$$I _ { n } = \int x ^ { n } \cos x \mathrm {~d} x$$

(a) Show that, for $n \geqslant 2$

$$I _ { n } = x ^ { n } \sin x + n x ^ { n - 1 } \cos x - n ( n - 1 ) I _ { n - 2 }$$

(b) Hence find the functions $\mathrm { f } ( x )$ and $\mathrm { g } ( x )$ such that
\end{enumerate}

\hfill \mbox{\textit{Edexcel F3 2020 Q4 [9]}}