5.
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{b896c631-00a0-46c5-bce9-16d65f6e3095-09_364_422_269_753}
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\caption{Figure 2}
\end{figure}
Two particles \(A\) and \(B\) have masses \(2 m\) and \(3 m\) respectively. The particles are connected by a light inextensible string which passes over a smooth light fixed pulley. The system is held at rest with the string taut. The hanging parts of the string are vertical and \(A\) and \(B\) are above a horizontal plane, as shown in Figure 2. The system is released from rest.
- Show that the tension in the string immediately after the particles are released is \(\frac { 12 } { 5 } m g\).
After descending \(1.5 \mathrm {~m} , B\) strikes the plane and is immediately brought to rest. In the subsequent motion, \(A\) does not reach the pulley.
- Find the distance travelled by \(A\) between the instant when \(B\) strikes the plane and the instant when the string next becomes taut.
Given that \(m = 0.5 \mathrm {~kg}\),
- find the magnitude of the impulse on \(B\) due to the impact with the plane.