Edexcel FP2 2018 June — Question 4 7 marks

Exam BoardEdexcel
ModuleFP2 (Further Pure Mathematics 2)
Year2018
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSolve |quadratic| compared to linear: algebraic inequality
DifficultyChallenging +1.2 This is a Further Maths modulus inequality requiring systematic case analysis (splitting at critical points where x²-2=0 and considering sign changes), solving two quadratic inequalities, and careful combination of solution sets. More demanding than standard A-level but routine for FP2 students who know the technique.
Spec1.02l Modulus function: notation, relations, equations and inequalities

4. Use algebra to find the set of values of \(x\) for which $$\left| x ^ { 2 } - 2 \right| > 4 x$$

Question 4:
AnswerMarks Guidance
\(x^2 - 2 > 4x\)
Answer/WorkingMark Guidance
\(x^2 - 2 = 4x\) ①M1 Form 3TQ and attempt to solve - may be implied by correct value(s) (allow decimals 4.449, -0.449)
\(x = 2 \pm \sqrt{6}\) or \(2 + \sqrt{6}\)A1 Correct exact values or value (NB: Corresponding 3TQ must have been seen)
\(x^2 - 2 = -4x\) ②M1 Form 3TQ and attempt to solve - may be implied by correct value(s) (allow decimals -4.449, 0.449)
\(x = -2 \pm \sqrt{6}\) or \(x = -2 + \sqrt{6}\)A1 Correct exact values or value (NB: Corresponding 3TQ must have been seen)
\(x >\) larger root of ① or \(x <\) larger root of ②dM1 Forms at least one of the required inequalities using their exact values. Must be a strict inequality. Depends on either previous M mark
One of \(x < -2+\sqrt{6}\) or \(x > 2+\sqrt{6}\)A1 Or exact equivalent
Both of \(x < -2+\sqrt{6}\) or \(x > 2+\sqrt{6}\)A1 No others seen. Exact equivalents allowed. Allow "or" or "and" but not \(\cap\) if set notation used
ALT method:
AnswerMarks Guidance
Answer/WorkingMark Guidance
\((x^2-2)^2 = 16x^2\)M1 Square both sides and attempt to solve quadratic in \(x^2\) - may be implied by correct value(s) (allow decimals 19.79, -0.202)
\(x^2 = 10 \pm \sqrt{96}\)A1 \(x^2 = 10 \pm 4\sqrt{6}\) oe
\(x = 2\pm\sqrt{6}\) and \(x = -2\pm\sqrt{6}\) (\(x = 2+\sqrt{6}\) and \(x = -2+\sqrt{6}\) sufficient)M1A1 Valid attempt required to find exact form for \(x\) e.g. \((a+\sqrt{b})^2 = 10\pm\sqrt{96}\)
\(x >\) largest root or \(x <\) 2nd largest rootdM1 As main scheme
As main schemeA1, A1 As main scheme
Total: 7
## Question 4:

$|x^2 - 2| > 4x$

| Answer/Working | Mark | Guidance |
|---|---|---|
| $x^2 - 2 = 4x$ ① | M1 | Form 3TQ **and** attempt to solve - may be implied by correct value(s) (allow decimals 4.449, -0.449) |
| $x = 2 \pm \sqrt{6}$ or $2 + \sqrt{6}$ | A1 | Correct exact values or value (NB: Corresponding 3TQ must have been seen) |
| $x^2 - 2 = -4x$ ② | M1 | Form 3TQ **and** attempt to solve - may be implied by correct value(s) (allow decimals -4.449, 0.449) |
| $x = -2 \pm \sqrt{6}$ or $x = -2 + \sqrt{6}$ | A1 | Correct exact values or value (NB: Corresponding 3TQ must have been seen) |
| $x >$ larger root of ① or $x <$ larger root of ② | dM1 | Forms at least one of the required inequalities using their exact values. Must be a strict inequality. Depends on **either** previous M mark |
| One of $x < -2+\sqrt{6}$ or $x > 2+\sqrt{6}$ | A1 | Or exact equivalent |
| Both of $x < -2+\sqrt{6}$ or $x > 2+\sqrt{6}$ | A1 | No others seen. Exact equivalents allowed. Allow "or" or "and" but not $\cap$ if set notation used |

**ALT method:**

| Answer/Working | Mark | Guidance |
|---|---|---|
| $(x^2-2)^2 = 16x^2$ | M1 | Square both sides **and** attempt to solve quadratic in $x^2$ - may be implied by correct value(s) (allow decimals 19.79, -0.202) |
| $x^2 = 10 \pm \sqrt{96}$ | A1 | $x^2 = 10 \pm 4\sqrt{6}$ oe |
| $x = 2\pm\sqrt{6}$ and $x = -2\pm\sqrt{6}$ ($x = 2+\sqrt{6}$ and $x = -2+\sqrt{6}$ sufficient) | M1A1 | Valid attempt required to find exact form for $x$ e.g. $(a+\sqrt{b})^2 = 10\pm\sqrt{96}$ |
| $x >$ largest root or $x <$ 2nd largest root | dM1 | As main scheme |
| As main scheme | A1, A1 | As main scheme |

**Total: 7**

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4. Use algebra to find the set of values of $x$ for which

$$\left| x ^ { 2 } - 2 \right| > 4 x$$

\hfill \mbox{\textit{Edexcel FP2 2018 Q4 [7]}}