Edexcel FP2 2007 June — Question 9 5 marks

Exam BoardEdexcel
ModuleFP2 (Further Pure Mathematics 2)
Year2007
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFirst order differential equations (integrating factor)
TypeIterative/numerical methods
DifficultyStandard +0.3 This is a straightforward application of given numerical approximation formulas (Euler's method and midpoint method) with explicit instructions. Students simply substitute values into provided formulas and perform basic arithmetic—no derivation, conceptual understanding of numerical methods, or problem-solving required. Slightly above trivial due to careful arithmetic with decimals, but easier than average A-level questions.
Spec1.09e Iterative method failure: convergence conditions4.10a General/particular solutions: of differential equations

9. $$\frac { \mathrm { d } y } { \mathrm {~d} x } = y \mathrm { e } ^ { x ^ { 2 } } .$$ It is given that \(y = 0.2\) at \(x = 0\).
  1. Use the approximation \(\frac { y _ { 1 } - y _ { 0 } } { h } \approx \left( \frac { \mathrm {~d} y } { \mathrm {~d} x } \right) _ { 0 }\), with \(h = 0.1\), to obtain an estimate of the value of \(y\) at \(x = 0.1\).
  2. Use your answer to part (a) and the approximation \(\frac { y _ { 2 } - y _ { 0 } } { 2 h } \approx \left( \frac { \mathrm {~d} y } { \mathrm {~d} x } \right) _ { 1 }\), with \(h = 0.1\), to obtain an estimate of the value of \(y\) at \(x = 0.2\). Gives your answer to 4 decimal places.
    (Total 5 marks)

AnswerMarks Guidance
(a) \(\frac{y_1 - 0.2}{0.1} \approx \left(\frac{dy}{dx}\right)_0 = 0.2 \times e^0(= 0.2)\)M1
\(y_1 \approx 0.22\)A12
(b) \(\left(\frac{dy}{dx}\right)_{0.2} \approx 0.22 \times e^{0.01} \approx 0.2222...\)B1
\(\frac{0.2222...}{0.2} \approx 0.2222...\)M1
\(y_2 \approx 0.2444\)cao A13
Total: [5]
**(a)** $\frac{y_1 - 0.2}{0.1} \approx \left(\frac{dy}{dx}\right)_0 = 0.2 \times e^0(= 0.2)$ | M1 |
$y_1 \approx 0.22$ | A12 |

**(b)** $\left(\frac{dy}{dx}\right)_{0.2} \approx 0.22 \times e^{0.01} \approx 0.2222...$ | B1 |
$\frac{0.2222...}{0.2} \approx 0.2222...$ | M1 |
$y_2 \approx 0.2444$ | cao | A13 |

**Total: [5]**

---
9.

$$\frac { \mathrm { d } y } { \mathrm {~d} x } = y \mathrm { e } ^ { x ^ { 2 } } .$$

It is given that $y = 0.2$ at $x = 0$.
\begin{enumerate}[label=(\alph*)]
\item Use the approximation $\frac { y _ { 1 } - y _ { 0 } } { h } \approx \left( \frac { \mathrm {~d} y } { \mathrm {~d} x } \right) _ { 0 }$, with $h = 0.1$, to obtain an estimate of the value of $y$ at $x = 0.1$.
\item Use your answer to part (a) and the approximation $\frac { y _ { 2 } - y _ { 0 } } { 2 h } \approx \left( \frac { \mathrm {~d} y } { \mathrm {~d} x } \right) _ { 1 }$, with $h = 0.1$, to obtain an estimate of the value of $y$ at $x = 0.2$.

Gives your answer to 4 decimal places.\\
(Total 5 marks)
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP2 2007 Q9 [5]}}