| Exam Board | CAIE |
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| Module | P1 (Pure Mathematics 1) |
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| Year | 2015 |
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| Session | November |
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| Topic | Trig Equations |
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4
- Show that the equation \(\frac { 4 \cos \theta } { \tan \theta } + 15 = 0\) can be expressed as
$$4 \sin ^ { 2 } \theta - 15 \sin \theta - 4 = 0$$
- Hence solve the equation \(\frac { 4 \cos \theta } { \tan \theta } + 15 = 0\) for \(0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }\).