Edexcel F1 2017 June — Question 6 8 marks

Exam BoardEdexcel
ModuleF1 (Further Pure Mathematics 1)
Year2017
SessionJune
Marks8
PaperDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeSum from n+1 to 2n or similar range
DifficultyStandard +0.3 This is a straightforward Further Maths question requiring algebraic manipulation of standard summation formulas (expanding r²(r+1) into r³+r²) and then using the difference method for part (b). While it involves multiple steps, the techniques are routine for F1 students with no novel insight required, making it slightly easier than average.
Spec1.04g Sigma notation: for sums of series4.06a Summation formulae: sum of r, r^2, r^3

6. (a) Use the standard results for \(\sum _ { r = 1 } ^ { n } r ^ { 2 }\) and for \(\sum _ { r = 1 } ^ { n } r ^ { 3 }\) to show that, for all positive integers \(n\), $$\sum _ { r = 1 } ^ { n } r ^ { 2 } ( r + 1 ) = \frac { n } { a } ( n + 1 ) ( n + 2 ) ( 3 n + b )$$ where \(a\) and \(b\) are integers to be found.
(b) Hence find the value of $$\sum _ { r = 25 } ^ { 49 } \left( r ^ { 2 } ( r + 1 ) + 2 \right)$$

6. (a) Use the standard results for $\sum _ { r = 1 } ^ { n } r ^ { 2 }$ and for $\sum _ { r = 1 } ^ { n } r ^ { 3 }$ to show that, for all positive integers $n$,

$$\sum _ { r = 1 } ^ { n } r ^ { 2 } ( r + 1 ) = \frac { n } { a } ( n + 1 ) ( n + 2 ) ( 3 n + b )$$

where $a$ and $b$ are integers to be found.\\
(b) Hence find the value of

$$\sum _ { r = 25 } ^ { 49 } \left( r ^ { 2 } ( r + 1 ) + 2 \right)$$

\hfill \mbox{\textit{Edexcel F1 2017 Q6 [8]}}