Edexcel F1 2024 January — Question 6 8 marks

Exam BoardEdexcel
ModuleF1 (Further Pure Mathematics 1)
Year2024
SessionJanuary
Marks8
PaperDownload PDF ↗
TopicNewton-Raphson method
TypeCompare Newton-Raphson with linear interpolation
DifficultyModerate -0.8 This is a routine Further Maths F1 question testing standard numerical methods procedures. Part (i) requires showing a sign change (straightforward substitution) and applying linear interpolation formula once. Part (ii) involves differentiating a polynomial/rational function and applying Newton-Raphson once. All steps are algorithmic with no problem-solving insight required—easier than average A-level questions.
Spec1.07i Differentiate x^n: for rational n and sums1.09a Sign change methods: locate roots1.09b Sign change methods: understand failure cases1.09d Newton-Raphson method

$$f ( x ) = x - 4 - \cos ( 5 \sqrt { x } ) \quad x > 0$$
  1. Show that the equation \(\mathrm { f } ( x ) = 0\) has a root \(\alpha\) in the interval [2.5, 3.5]
    [0pt]
  2. Use linear interpolation once on the interval [2.5, 3.5] to find an approximation to \(\alpha\), giving your answer to 2 decimal places.
    (ii) $$\operatorname { g } ( x ) = \frac { 1 } { 10 } x ^ { 2 } - \frac { 1 } { 2 x ^ { 2 } } + x - 11 \quad x > 0$$
  3. Determine \(\mathrm { g } ^ { \prime } ( x )\). The equation \(\mathrm { g } ( x ) = 0\) has a root \(\beta\) in the interval [6,7]
  4. Using \(x _ { 0 } = 6\) as a first approximation to \(\beta\), apply the Newton-Raphson procedure once to \(\mathrm { g } ( x )\) to find a second approximation to \(\beta\), giving your answer to 3 decimal places.

\begin{enumerate}
  \item (i)
\end{enumerate}

$$f ( x ) = x - 4 - \cos ( 5 \sqrt { x } ) \quad x > 0$$

(a) Show that the equation $\mathrm { f } ( x ) = 0$ has a root $\alpha$ in the interval [2.5, 3.5]\\[0pt]
(b) Use linear interpolation once on the interval [2.5, 3.5] to find an approximation to $\alpha$, giving your answer to 2 decimal places.\\
(ii)

$$\operatorname { g } ( x ) = \frac { 1 } { 10 } x ^ { 2 } - \frac { 1 } { 2 x ^ { 2 } } + x - 11 \quad x > 0$$

(a) Determine $\mathrm { g } ^ { \prime } ( x )$.

The equation $\mathrm { g } ( x ) = 0$ has a root $\beta$ in the interval [6,7]\\
(b) Using $x _ { 0 } = 6$ as a first approximation to $\beta$, apply the Newton-Raphson procedure once to $\mathrm { g } ( x )$ to find a second approximation to $\beta$, giving your answer to 3 decimal places.

\hfill \mbox{\textit{Edexcel F1 2024 Q6 [8]}}