Edexcel C4 2013 June — Question 1 4 marks

Exam BoardEdexcel
ModuleC4 (Core Mathematics 4)
Year2013
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPartial Fractions
TypeRepeated linear factor with distinct linear factor – decompose and integrate
DifficultyModerate -0.3 This is a standard partial fractions decomposition with a repeated linear factor. The technique is routine for C4: set up A/(2x+1) + B/(x+1) + C/(x+1)², multiply through, and solve by substitution or comparing coefficients. It requires methodical application of a well-practiced algorithm with no conceptual challenges or novel problem-solving.
Spec1.02y Partial fractions: decompose rational functions

  1. Express in partial fractions
$$\frac { 5 x + 3 } { ( 2 x + 1 ) ( x + 1 ) ^ { 2 } }$$

Question 1:
\[\frac{5x+3}{(2x+1)(x+1)^2} \equiv \frac{A}{(2x+1)} + \frac{B}{(x+1)} + \frac{C}{(x+1)^2}\]
AnswerMarks Guidance
Working/AnswerMark Guidance
At least one of \(A\) or \(C\) correctB1 At least one of "\(A\)" or "\(C\)" are correct
\(A = 2,\ C = 2\)B1 cso Breaks up partial fraction correctly into three terms and both \(A=2\) and \(C=2\)
\(5x+3 \equiv A(x+1)^2 + B(2x+1)(x+1) + C(2x+1)\); attempts to find value of \(A\), \(B\), or \(C\)M1 Writes down a correct identity and attempts to find the value of either one of "\(A\)" or "\(B\)" or "\(C\)" (by substitution or comparing coefficients)
\(B = -1\)A1 cso Correct value for "\(B\)" found using a correct identity, following from their partial fraction decomposition
Final answer: \(\dfrac{5x+3}{(2x+1)(x+1)^2} \equiv \dfrac{2}{(2x+1)} - \dfrac{1}{(x+1)} + \dfrac{2}{(x+1)^2}\)
Total: [4]
Notes:
- Candidates assign their own \(A\), \(B\), \(C\)
- M1 can be implied by correct working
- If no partial fraction decomposition shown: 2nd B1 can follow from correct identity; A1 can be awarded for correct \(B\) if partial fractions written at end
- Correct partial fraction from no working scores B1B1M1A1
- The correct partial fraction from no working scores B1B1M1A1
## Question 1:

$$\frac{5x+3}{(2x+1)(x+1)^2} \equiv \frac{A}{(2x+1)} + \frac{B}{(x+1)} + \frac{C}{(x+1)^2}$$

| Working/Answer | Mark | Guidance |
|---|---|---|
| At least one of $A$ or $C$ correct | B1 | At least one of "$A$" or "$C$" are correct |
| $A = 2,\ C = 2$ | B1 **cso** | Breaks up partial fraction correctly into three terms **and** both $A=2$ and $C=2$ |
| $5x+3 \equiv A(x+1)^2 + B(2x+1)(x+1) + C(2x+1)$; attempts to find value of $A$, $B$, or $C$ | M1 | Writes down a **correct identity** and attempts to find the value of either one of "$A$" or "$B$" or "$C$" (by substitution or comparing coefficients) |
| $B = -1$ | A1 **cso** | Correct value for "$B$" found using a correct identity, following from their partial fraction decomposition |

**Final answer:** $\dfrac{5x+3}{(2x+1)(x+1)^2} \equiv \dfrac{2}{(2x+1)} - \dfrac{1}{(x+1)} + \dfrac{2}{(x+1)^2}$

**Total: [4]**

**Notes:**
- Candidates assign their own $A$, $B$, $C$
- M1 can be implied by correct working
- If no partial fraction decomposition shown: 2nd B1 can follow from correct identity; A1 can be awarded for correct $B$ if partial fractions written at end
- Correct partial fraction from no working scores B1B1M1A1
- The correct partial fraction from no working scores **B1B1M1A1**
\begin{enumerate}
  \item Express in partial fractions
\end{enumerate}

$$\frac { 5 x + 3 } { ( 2 x + 1 ) ( x + 1 ) ^ { 2 } }$$

\hfill \mbox{\textit{Edexcel C4 2013 Q1 [4]}}