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The diagram shows a sector \(O A B\) of a circle with centre \(O\) and radius \(O A\). The angle \(A O B\) is \(\theta\) radians. \(M\) is the mid-point of \(O A\). The ratio of areas \(O M B : M A B\) is 2:3.
- Show that \(\theta = 1.25 \sin \theta\).
The equation \(\theta = 1.25 \sin \theta\) has only one root for \(\theta > 0\).
- This root can be found by using the iterative formula \(\theta _ { n + 1 } = 1.25 \sin \theta _ { n }\) with a starting value of \(\theta _ { 1 } = 0.5\).
- Write down the values of \(\theta _ { 2 } , \theta _ { 3 }\) and \(\theta _ { 4 }\).
- Hence find the value of this root correct to \(\mathbf { 3 }\) significant figures.
- The diagram in the Printed Answer Booklet shows the graph of \(y = 1.25 \sin \theta\), for \(0 \leqslant \theta \leqslant \pi\).
- Use this diagram to show how the iterative process used in (b) converges to this root.
- State the type of convergence.
- Draw a suitable diagram to show why using an iterative process with the formula \(\theta _ { n + 1 } = \sin ^ { - 1 } \left( 0.8 \theta _ { n } \right)\) does not converge to the root found in (b).