6.
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{71cd126f-1c7d-4e37-a26d-7ff98a74fd79-22_481_1139_189_463}
\captionsetup{labelformat=empty}
\caption{Figure 2}
\end{figure}
Figure 2 shows the first few iterations in the construction of a curve, \(L\).
Starting with a straight line \(L _ { 0 }\) of length 4 , the middle half of this line is replaced by three sides of a trapezium above \(L _ { 0 }\) as shown, such that the length of each of these sides is \(\frac { 1 } { 4 }\) of the length of \(L _ { 0 }\)
After the first iteration each line segment has length one.
In subsequent iterations, each line segment parallel to \(L _ { 0 }\) similarly has its middle half replaced by three sides of a trapezium above that line segment, with each side \(\frac { 1 } { 4 }\) the length of that line segment.
Line segments in \(L _ { n }\) are either parallel to \(L _ { 0 }\) or are sloped.
- Show that the length of \(L _ { 2 }\) is \(\frac { 23 } { 4 }\)
- Write down the number of
- line segments in \(L _ { n }\) that are parallel to \(L _ { 0 }\)
- sloped line segments in \(L _ { 2 }\) that are not in \(L _ { 1 }\)
- new sloped line segments that are created by the ( \(n + 1\) )th iteration.
- Hence find the length of \(L _ { n }\) as \(n \rightarrow \infty\)
The area enclosed between \(L _ { 0 }\) and \(L _ { n }\) is \(A _ { n }\)
- Find the value of \(A _ { 1 }\)
- Find, in terms of \(n\), an expression for \(A _ { n + 1 } - A _ { n }\)
- Hence find the value of \(A _ { n }\) as \(n \rightarrow \infty\)
The same construction as described above is applied externally to the three sides of an equilateral triangle of side length \(a\).
Given that the limit of the area of the resulting shape is \(26 \sqrt { 3 }\) - find the value of \(a\).