Maclaurin series of shifted function

A question is this type if and only if it asks for a Maclaurin series (expansion about x = 0) of a function that has been horizontally shifted, such as f(x + a).

4 questions · Standard +0.6

4.08a Maclaurin series: find series for function
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CAIE Further Paper 2 2020 November Q1
5 marks Standard +0.8
1 Find the Maclaurin's series for \(\tan \left( x + \frac { 1 } { 4 } \pi \right)\) up to and including the term in \(x ^ { 2 }\).
OCR MEI FP2 2010 June Q1
19 marks Standard +0.8
1
    1. Given that \(\mathrm { f } ( t ) = \arcsin t\), write down an expression for \(\mathrm { f } ^ { \prime } ( t )\) and show that $$\mathrm { f } ^ { \prime \prime } ( t ) = \frac { t } { \left( 1 - t ^ { 2 } \right) ^ { \frac { 3 } { 2 } } }$$
    2. Show that the Maclaurin expansion of the function \(\arcsin \left( x + \frac { 1 } { 2 } \right)\) begins $$\frac { \pi } { 6 } + \frac { 2 } { \sqrt { 3 } } x$$ and find the term in \(x ^ { 2 }\).
  1. Sketch the curve with polar equation \(r = \frac { \pi a } { \pi + \theta }\), where \(a > 0\), for \(0 \leqslant \theta < 2 \pi\). Find, in terms of \(a\), the area of the region bounded by the part of the curve for which \(0 \leqslant \theta \leqslant \pi\) and the lines \(\theta = 0\) and \(\theta = \pi\).
  2. Find the exact value of the integral $$\int _ { 0 } ^ { \frac { 3 } { 2 } } \frac { 1 } { 9 + 4 x ^ { 2 } } \mathrm {~d} x$$
CAIE Further Paper 2 2023 November Q3
6 marks Challenging +1.2
Find the first three terms in the Maclaurin's series for \(\tanh^{-1}\left(\frac{1}{2}e^t\right)\) in the form \(\frac{1}{2}\ln a + bx + cx^2\), giving the exact values of the constants \(a\), \(b\) and \(c\). [6]
SPS SPS FM Pure 2025 February Q13
6 marks Moderate -0.3
  1. Write down the Maclaurin series of \(e^x\), in ascending power of \(x\), up to and including the term in \(x^3\) [1]
  2. Hence, without differentiating, determine the Maclaurin series of $$e^{(x^3-1)}$$ in ascending powers of \(x\), up to and including the term in \(x^3\), giving each coefficient in simplest form. [5]