Quadratic in x^(1/4) - substitution u = x^(1/4)

Solve equations where substituting u = x^(1/4) reduces the equation to a standard quadratic in u, e.g. 3x^(1/2) - 8x^(1/4) + 4 = 0, 2y^(1/2) - 7y^(1/4) + 3 = 0.

2 questions · Standard +0.0

1.02f Solve quadratic equations: including in a function of unknown

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OCR C1 2011 June Q6

5 marks Moderate -0.3

6 Solve the equation \(3 x ^ { \frac { 1 } { 2 } } - 8 x ^ { \frac { 1 } { 4 } } + 4 = 0\).

OCR C1 2016 June Q4

5 marks Standard +0.3

4 Solve the equation \(2 y ^ { \frac { 1 } { 2 } } - 7 y ^ { \frac { 1 } { 4 } } + 3 = 0\).