9 Water is poured into a tank at a constant rate of \(500 \mathrm {~cm} ^ { 3 }\) per second. The depth of water in the tank, \(t\) seconds after filling starts, is \(h \mathrm {~cm}\). When the depth of water in the tank is \(h \mathrm {~cm}\), the volume, \(V \mathrm {~cm} ^ { 3 }\), of water in the tank is given by the formula \(V = \frac { 4 } { 3 } ( 25 + h ) ^ { 3 } - \frac { 62500 } { 3 }\).
- Find the rate at which \(h\) is increasing at the instant when \(h = 10 \mathrm {~cm}\).
- At another instant, the rate at which \(h\) is increasing is 0.075 cm per second.
Find the value of \(V\) at this instant.