Differentiate logarithmic functions

Find the derivative of functions involving ln(x), ln(f(x)), or (ln x)^n, often combined with other functions.

5 questions · Moderate -0.8

1.07l Derivative of ln(x): and related functions
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AQA C3 2010 June Q3
12 marks Moderate -0.3
3
  1. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) when:
    1. \(\quad y = \ln ( 5 x - 2 )\);
    2. \(y = \sin 2 x\).
  2. The functions f and g are defined with their respective domains by $$\begin{array} { l l } \mathrm { f } ( x ) = \ln ( 5 x - 2 ) , & \text { for real values of } x \text { such that } x \geqslant \frac { 1 } { 2 } \\ \mathrm {~g} ( x ) = \sin 2 x , & \text { for real values of } x \text { in the interval } - \frac { \pi } { 4 } \leqslant x \leqslant \frac { \pi } { 4 } \end{array}$$
    1. Find the range of f .
    2. Find an expression for \(\operatorname { gf } ( x )\).
    3. Solve the equation \(\operatorname { gf } ( x ) = 0\).
    4. The inverse of g is \(\mathrm { g } ^ { - 1 }\). Find \(\mathrm { g } ^ { - 1 } ( x )\).
AQA Paper 1 2021 June Q2
1 marks Easy -1.8
2 Given that \(y = \ln ( 5 x )\) find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) Circle your answer. $$\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 1 } { x } \quad \frac { \mathrm {~d} y } { \mathrm {~d} x } = \frac { 1 } { 5 x } \quad \frac { \mathrm {~d} y } { \mathrm {~d} x } = \frac { 5 } { x } \quad \frac { \mathrm {~d} y } { \mathrm {~d} x } = \ln 5$$
Pre-U Pre-U 9794/2 2013 November Q7
Moderate -0.3
7
  1. Differentiate \(3 \ln \left( x ^ { 2 } + 1 \right)\).
  2. Find \(\int \frac { x ^ { 2 } } { 3 - 4 x ^ { 3 } } \mathrm {~d} x\).
OCR C4 Q1
4 marks Moderate -0.8
Differentiate each of the following with respect to \(x\) and simplify your answers.
  1. \(\ln(\cos x)\) [2]
  2. \(x^2 \sin 3x\) [2]
SPS SPS SM 2021 November Q1
8 marks Moderate -0.8
Find \(\frac{dy}{dx}\) for the following functions, simplifying your answers as far as possible.
  1. \(y = \cos x - 2 \sin 2x\) [2]
  2. \(y = \frac{1}{2}x^4 + 2x^4 \ln x\) [3]
  3. \(y = \frac{2e^{3x} - 1}{3e^{3x} - 1}\) [3]