Sum of first n terms

A question is this type if and only if it asks to find the sum of the first n terms of a geometric progression for a specific value of n (not sum to infinity).

11 questions · Moderate -0.6

1.04i Geometric sequences: nth term and finite series sum
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CAIE P1 2004 November Q2
6 marks Easy -1.3
2 Find
  1. the sum of the first ten terms of the geometric progression \(81,54,36 , \ldots\),
  2. the sum of all the terms in the arithmetic progression \(180,175,170 , \ldots , 25\).
OCR C2 Q1
4 marks Moderate -0.8
  1. Evaluate
$$\sum _ { r = 1 } ^ { 12 } \left( 5 \times 2 ^ { r } \right)$$
OCR C2 2009 June Q8
11 marks Moderate -0.3
8 \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{3836b0e7-95e6-4634-bb1e-c99b7ae3c8ba-3_378_467_269_840} \captionsetup{labelformat=empty} \caption{Fig. 1}
\end{figure} Fig. 1 shows a sector \(A O B\) of a circle, centre \(O\) and radius \(O A\). The angle \(A O B\) is 1.2 radians and the area of the sector is \(60 \mathrm {~cm} ^ { 2 }\).
  1. Find the perimeter of the sector. A pattern on a T-shirt, the start of which is shown in Fig. 2, consists of a sequence of similar sectors. The first sector in the pattern is sector \(A O B\) from Fig. 1, and the area of each successive sector is \(\frac { 3 } { 5 }\) of the area of the previous one. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{3836b0e7-95e6-4634-bb1e-c99b7ae3c8ba-3_362_1011_1263_568} \captionsetup{labelformat=empty} \caption{Fig. 2}
    \end{figure}
  2. (a) Find the area of the fifth sector in the pattern.
    (b) Find the total area of the first ten sectors in the pattern.
    (c) Explain why the total area will never exceed a certain limit, no matter how many sectors are used, and state the value of this limit.
OCR C2 2011 June Q7
9 marks Moderate -0.8
7
  1. The first term of a geometric progression is 7 and the common ratio is - 2 .
    1. Find the ninth term.
    2. Find the sum of the first 15 terms.
  2. The first term of an arithmetic progression is 7 and the common difference is - 2 . The sum of the first \(N\) terms is - 2900 . Find the value of \(N\).
OCR C2 2015 June Q1
5 marks Moderate -0.8
1 A geometric progression has first term 3 and second term - 6 .
  1. State the value of the common ratio.
  2. Find the value of the eleventh term.
  3. Find the sum of the first twenty terms.
AQA C2 2007 June Q2
7 marks Moderate -0.8
2 The \(n\)th term of a geometric sequence is \(u _ { n }\), where $$u _ { n } = 3 \times 4 ^ { n }$$
  1. Find the value of \(u _ { 1 }\) and show that \(u _ { 2 } = 48\).
  2. Write down the common ratio of the geometric sequence.
    1. Show that the sum of the first 12 terms of the geometric sequence is \(4 ^ { k } - 4\), where \(k\) is an integer.
    2. Hence find the value of \(\sum _ { n = 2 } ^ { 12 } u _ { n }\).
CAIE P3 2018 June Q3
5 marks Standard +0.3
The common ratio of a geometric progression is 0.99. Express the sum of the first 100 terms as a percentage of the sum to infinity, giving your answer correct to 2 significant figures. [5]
OCR C2 2007 January Q6
7 marks Moderate -0.8
  1. Find and simplify the first four terms in the expansion of \((1 + 4x)^7\) in ascending powers of \(x\). [4]
  2. In the expansion of $$(3 + ax)(1 + 4x)^7,$$ the coefficient of \(x^2\) is 1001. Find the value of \(a\). [3]
OCR MEI C2 Q2
5 marks Moderate -0.8
A geometric progression has a positive common ratio. Its first three terms are 32, \(b\) and 12.5. Find the value of \(b\) and find also the sum of the first 15 terms of the progression. [5]
SPS SPS FM 2020 December Q13
5 marks Standard +0.3
A series is given by $$\sum_{r=1}^k 9^{r-1}$$
  1. Write down a formula for the sum of this series. [1]
  2. Prove by induction that \(P(n) = 9^n - 8n - 1\) is divisible by 64 if \(n\) is a positive integer greater than 1. [4]
OCR H240/02 2018 December Q6
8 marks Moderate -0.8
The table shows information about three geometric series. The three geometric series have different common ratios.
First termCommon ratioNumber of termsLast term
Series 112\(n_1\)1024
Series 21\(r_2\)\(n_2\)1024
Series 31\(r_3\)\(n_3\)1024
  1. Find \(n_1\). [2]
  2. Given that \(r_2\) is an integer less than 10, find the value of \(r_2\) and the value of \(n_2\). [2]
  3. Given that \(r_3\) is not an integer, find a possible value for the sum of all the terms in Series 3. [4]