Energy methods in SHM

A question is this type if and only if it explicitly requires using energy conservation or kinetic energy to solve for motion parameters in SHM.

2 questions · Challenging +1.2

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CAIE FP2 2019 June Q11 EITHER
Challenging +1.2
A light spring has natural length \(a\) and modulus of elasticity \(k m g\). The spring lies on a smooth horizontal surface with one end attached to a fixed point \(O\). A particle \(P\) of mass \(m\) is attached to the other end of the spring. The system is in equilibrium with \(O P = a\). The particle is projected towards \(O\) with speed \(u\) and comes to instantaneous rest when \(O P = \frac { 3 } { 4 } a\).
  1. Use an energy method to show that \(k = \frac { 16 u ^ { 2 } } { a g }\).
  2. Show that \(P\) performs simple harmonic motion and find the period of this motion, giving your answer in terms of \(u\) and \(a\).
  3. Find, in terms of \(u\) and \(a\), the time that elapses before \(P\) first loses \(25 \%\) of its initial kinetic energy.
Edexcel M3 2007 June Q7
15 marks Challenging +1.2
\includegraphics{figure_1} A light elastic string, of natural length \(3l\) and modulus of elasticity \(\lambda\), has its ends attached to two points \(A\) and \(B\), where \(AB = 3l\) and \(AB\) is horizontal. A particle \(P\) of mass \(m\) is attached to the mid-point of the string. Given that \(P\) rests in equilibrium at a distance \(2l\) below \(AB\), as shown in Figure 1,
  1. show that \(\lambda = \frac{15mg}{16}\) [9]
The particle is pulled vertically downwards from its equilibrium position until the total length of the elastic string is \(7.8l\). The particle is released from rest.
  1. Show that \(P\) comes to instantaneous rest on the line \(AB\). [6]