Force depends on time t

A question is this type if and only if the force or acceleration is given as a function of time t (e.g., F = 3t, a = e^(-t/6)), requiring integration of dv/dt = F(t)/m with respect to time.

18 questions · Standard +0.4

6.06a Variable force: dv/dt or v*dv/dx methods
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CAIE M2 2012 June Q4
7 marks Standard +0.3
4 A particle \(P\) of mass 0.25 kg moves in a straight line on a smooth horizontal surface. At time \(t \mathrm {~s}\) the velocity of \(P\) is \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\). A variable force of magnitude \(3 t \mathrm {~N}\) opposes the motion of \(P\).
  1. Given that \(P\) comes to rest when \(t = 3\), find \(v\) when \(t = 0\).
  2. Calculate the distance travelled by \(P\) in the interval \(0 \leqslant t \leqslant 3\).
CAIE M2 2016 June Q5
10 marks Standard +0.3
5 A particle \(P\) of mass 0.4 kg is placed at rest at a point \(A\) on a rough horizontal surface. A horizontal force, directed away from \(A\) and with magnitude \(0.6 t \mathrm {~N}\), acts on \(P\), where \(t \mathrm {~s}\) is the time after \(P\) is placed at \(A\). The coefficient of friction between \(P\) and the surface is 0.3 , and \(P\) has displacement from \(A\) of \(x \mathrm {~m}\) at time \(t \mathrm {~s}\).
  1. Show that \(P\) starts to move when \(t = 2\). Show also that when \(P\) is in motion it has acceleration \(( 1.5 t - 3 ) \mathrm { m } \mathrm { s } ^ { - 2 }\).
  2. Express the velocity of \(P\) in terms of \(t\), for \(t \geqslant 2\).
  3. Express \(x\) in terms of \(t\), for \(t \geqslant 2\).
Edexcel M3 2017 January Q2
7 marks Standard +0.3
2. A particle \(P\) of mass 0.6 kg is moving along the positive \(x\)-axis in the positive direction. The only force acting on \(P\) acts in the direction of \(x\) increasing and has magnitude \(\left( 3 t + \frac { 1 } { 2 } \right) \mathrm { N }\), where \(t\) seconds is the time after \(P\) leaves the origin \(O\). When \(t = 0 , P\) is at rest at \(O\).
  1. Find an expression, in terms of \(t\), for the velocity of \(P\) at time \(t\) seconds. The particle passes through the point \(A\) with speed \(\frac { 10 } { 3 } \mathrm {~ms} ^ { - 1 }\).
  2. Find the distance \(O A\).
Edexcel M3 2018 January Q3
10 marks Standard +0.3
  1. A particle \(P\) of mass 0.4 kg moves along the \(x\)-axis in the positive direction. At time \(t = 0 , P\) passes through the origin \(O\) with speed \(10 \mathrm {~m} \mathrm {~s} ^ { - 1 }\). At time \(t\) seconds \(P\) is \(x\) metres from \(O\) and the speed of \(P\) is \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\). The resultant force acting on \(P\) has magnitude \(\frac { 8 } { ( t + 4 ) ^ { 2 } } \mathrm {~N}\) and is directed towards \(O\).
    1. Show that \(v = \frac { 20 } { t + 4 } + 5\)
    When \(v = 6 , x = a + b \ln 5\), where \(a\) and \(b\) are integers.
  2. Using algebraic integration, find the value of \(a\) and the value of \(b\).
Edexcel M3 2003 January Q5
12 marks Standard +0.8
5. A car of mass 800 kg moves along a horizontal straight road. At time \(t\) seconds, the resultant force acting on the car has magnitude \(\frac { 48000 } { ( t + 2 ) ^ { 2 } }\) newtons, acting in the direction of the motion of the car. When \(t = 0\), the car is at rest.
  1. Show that the speed of the car approaches a limiting value as \(t\) increases and find this value.
  2. Find the distance moved by the car in the first 6 seconds of its motion.
Edexcel M3 2009 January Q1
7 marks Standard +0.3
  1. A particle \(P\) of mass 3 kg is moving in a straight line. At time \(t\) seconds, \(0 \leqslant t \leqslant 4\), the only force acting on \(P\) is a resistance to motion of magnitude \(\left( 9 + \frac { 15 } { ( t + 1 ) ^ { 2 } } \right) \mathrm { N }\). At time \(t\) seconds the velocity of \(P\) is \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\). When \(t = 4 , v = 0\).
Find the value of \(v\) when \(t = 0\).
Edexcel M3 2010 January Q1
7 marks Standard +0.3
  1. A particle \(P\) of mass 0.5 kg is moving along the positive \(x\)-axis. At time \(t\) seconds, \(P\) is moving under the action of a single force of magnitude \([ 4 + \cos ( \pi t ) ] \mathrm { N }\), directed away from the origin. When \(t = 1\), the particle \(P\) is moving away from the origin with speed \(6 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
Find the speed of \(P\) when \(t = 1.5\), giving your answer to 3 significant figures.
Edexcel M3 2013 January Q3
10 marks Standard +0.8
  1. A particle \(P\) of mass 0.6 kg is moving along the \(x\)-axis in the positive direction. At time \(t = 0 , P\) passes through the origin \(O\) with speed \(15 \mathrm {~ms} ^ { - 1 }\). At time \(t\) seconds the distance \(O P\) is \(x\) metres, the speed of \(P\) is \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\) and the resultant force acting on \(P\) has magnitude \(\frac { 12 } { ( t + 2 ) ^ { 2 } }\) newtons. The resultant force is directed towards \(O\).
    1. Show that \(v = 5 \left( \frac { 4 } { t + 2 } + 1 \right)\).
    2. Find the value of \(x\) when \(t = 5\)
Edexcel M3 2010 June Q6
12 marks Standard +0.3
  1. At time \(t = 0\), a particle \(P\) is at the origin \(O\) moving with speed \(2 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) along the \(x\)-axis in the positive \(x\)-direction. At time \(t\) seconds \(( t > 0 )\), the acceleration of \(P\) has magnitude \(\frac { 3 } { ( t + 1 ) ^ { 2 } } \mathrm {~m} \mathrm {~s} ^ { - 2 }\) and is directed towards \(O\).
    1. Show that at time \(t\) seconds the velocity of \(P\) is \(\left( \frac { 3 } { t + 1 } - 1 \right) \mathrm { m } \mathrm { s } ^ { - 1 }\).
    2. Find, to 3 significant figures, the distance of \(P\) from \(O\) when \(P\) is instantaneously at rest.
Edexcel M3 2013 June Q2
9 marks Standard +0.3
2. A particle \(P\) of mass 0.5 kg is moving along the positive \(x\)-axis in the positive \(x\)-direction. The only force on \(P\) is a force of magnitude \(\left( 2 t + \frac { 1 } { 2 } \right) \mathrm { N }\) acting in the direction of \(x\) increasing, where \(t\) seconds is the time after \(P\) leaves the origin \(O\). When \(t = 0\), \(P\) is at rest at \(O\).
  1. Find an expression, in terms of \(t\), for the velocity of \(P\) at time \(t\) seconds. The particle passes through the point \(A\) with speed \(6 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  2. Find the distance \(O A\).
Edexcel M3 2015 June Q4
12 marks Standard +0.3
  1. A vehicle of mass 900 kg moves along a straight horizontal road. At time \(t\) seconds the resultant force acting on the vehicle has magnitude \(\frac { 63000 } { k t ^ { 2 } } \mathrm {~N}\), where \(k\) is a positive constant. The force acts in the direction of motion of the vehicle. At time \(t\) seconds, \(t \geqslant 1\), the speed of the vehicle is \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\) and the vehicle is a distance \(x\) metres from a fixed point \(O\) on the road. When \(t = 1\) the vehicle is at rest at \(O\) and when \(t = 4\) the speed of the vehicle is \(10.5 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
    1. Show that \(v = 14 - \frac { 14 } { t }\)
    2. Hence deduce that the speed of the vehicle never reaches \(14 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
    3. Use the trapezium rule, with 4 equal intervals, to estimate the value of \(x\) when \(v = 7\)
OCR Further Mechanics 2021 November Q5
12 marks Standard +0.8
5 A particle \(P\) of mass 3 kg moves on the \(x\)-axis under the action of a single force acting in the positive \(x\)-direction. At time \(t \mathrm {~s}\), where \(t \geqslant 0\), the displacement of \(P\) is \(x \mathrm {~m}\) and its velocity is \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\). The magnitude of the force acting is inversely proportional to \(( t + 1 ) ^ { 2 }\). Initially \(P\) is at rest at the point where \(x = 1\). When \(t = 1 , v = 2\).
  1. Show that \(\frac { \mathrm { dv } } { \mathrm { dt } } = \frac { \mathrm { k } } { 3 ( \mathrm { t } + 1 ) ^ { 2 } }\) where \(k\) is a constant.
  2. Find an expression for \(v\) in terms of \(t\).
  3. Find an expression for \(x\) in terms of \(t\). As \(t\) increases, \(v\) approaches a limiting value, \(\mathrm { V } _ { \mathrm { T } }\).
  4. Determine how far \(P\) is from its initial position at the instant when \(v\) is \(95 \%\) of \(\mathrm { V } _ { \mathrm { T } }\).
AQA M2 2006 June Q5
14 marks Standard +0.3
5 The graph shows a model for the resultant horizontal force on a car, which varies as it accelerates from rest for 20 seconds. The mass of the car is 1200 kg . \includegraphics[max width=\textwidth, alt={}, center]{c02cf013-365b-44e2-8c16-aa8209cbe250-4_373_1203_445_390}
  1. The acceleration of the car at time \(t\) seconds is \(a \mathrm {~m} \mathrm {~s} ^ { - 2 }\). Show that $$a = \frac { 2 } { 3 } + \frac { t } { 20 } , \text { for } 0 \leqslant t \leqslant 20$$
  2. Find an expression for the velocity of the car at time \(t\).
  3. Find the distance travelled by the car in the 20 seconds.
  4. An alternative model assumes that the resultant force increases uniformly from 900 to 2100 newtons during the 20 seconds. Which term in your expression for the velocity would change as a result of this modification? Explain why.
AQA M2 2010 June Q4
12 marks Standard +0.3
4 A particle has mass 200 kg and moves on a smooth horizontal plane. A single horizontal force, \(\left( 400 \cos \left( \frac { \pi } { 2 } t \right) \mathbf { i } + 600 t ^ { 2 } \mathbf { j } \right)\) newtons, acts on the particle at time \(t\) seconds. The unit vectors \(\mathbf { i }\) and \(\mathbf { j }\) are directed east and north respectively.
  1. Find the acceleration of the particle at time \(t\).
  2. When \(t = 4\), the velocity of the particle is \(( - 3 \mathbf { i } + 56 \mathbf { j } ) \mathrm { m } \mathrm { s } ^ { - 1 }\). Find the velocity of the particle at time \(t\).
  3. Find \(t\) when the particle is moving due west.
  4. Find the speed of the particle when it is moving due west.
    \includegraphics[max width=\textwidth, alt={}]{3ffa0a2b-aa7d-46eb-b92b-3e3ee59f235c-09_2484_1709_223_153}
CAIE Further Paper 3 2024 November Q5
3 marks Moderate -0.5
  1. Find the magnitude of \(F\) when \(t = 3\). [3]
Edexcel M3 Specimen Q6
12 marks Standard +0.8
At time \(t = 0\), a particle \(P\) is at the origin \(O\) moving with speed \(2\) m s\(^{-1}\) along the \(x\)-axis in the positive \(x\)-direction. At time \(t\) seconds \((t > 0)\), the acceleration of \(P\) has magnitude \(\frac{3}{(t+1)^2}\) m s\(^{-2}\) and is directed towards \(O\).
  1. Show that at time \(t\) seconds the velocity of \(P\) is \(\left(\frac{3}{t+1} - 1\right)\) m s\(^{-1}\). [5]
  2. Find, to 3 significant figures, the distance of \(P\) from \(O\) when \(P\) is instantaneously at rest. [7]
Edexcel M3 Q4
9 marks Standard +0.3
The acceleration \(a\) ms\(^{-2}\) of a particle \(P\) moving in a straight line away from a fixed point \(O\) is given by \(a = \frac{k}{1+t}\), where \(t\) is the time that has elapsed since \(P\) left \(O\), and \(k\) is a constant.
  1. By solving a suitable differential equation, find an expression for the velocity \(v\) ms\(^{-1}\) of \(P\) in terms of \(t\), \(k\) and another constant \(c\). [3 marks]
Given that \(v = 0\) when \(t = 0\) and that \(v = 4\) when \(t = 2\),
  1. show that \(v \ln 3 = 4 \ln (1 + t)\). [3 marks]
  2. Calculate the time when \(P\) has a speed of 8 ms\(^{-1}\). [3 marks]
OCR M3 2010 June Q4
11 marks Standard +0.3
\(O\) is a fixed point on a horizontal plane. A particle \(P\) of mass \(0.25\) kg is released from rest at \(O\) and moves in a straight line on the plane. At time \(t\) s after release the only horizontal force acting on \(P\) has magnitude $$\frac{1}{2400}(144 - t^2) \text{ N} \quad \text{for } 0 \leqslant t \leqslant 12$$ and $$\frac{1}{2400}(t^2 - 144) \text{ N} \quad \text{for } t \geqslant 12.$$ The force acts in the direction of \(P\)'s motion. \(P\)'s velocity at time \(t\) s is \(v\) m s\(^{-1}\).
  1. Find an expression for \(v\) in terms of \(t\), valid for \(t \geqslant 12\), and hence show that \(v\) is three times greater when \(t = 24\) than it is when \(t = 12\). [8]
  2. Sketch the \((t, v)\) graph for \(0 \leqslant t \leqslant 24\). [3]