Find factor then solve

No factor is given; you must first use the factor theorem to find a factor by testing values, then factorise and solve completely.

6 questions · Moderate -0.3

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OCR C2 2011 June Q6
8 marks Moderate -0.8
6 The cubic polynomial \(\mathrm { f } ( x )\) is defined by \(\mathrm { f } ( x ) = x ^ { 3 } + x ^ { 2 } - 11 x + 10\).
  1. Use the factor theorem to find a factor of \(\mathrm { f } ( x )\).
  2. Hence solve the equation \(\mathrm { f } ( x ) = 0\), giving each root in an exact form.
OCR MEI Paper 3 2023 June Q4
4 marks Moderate -0.8
4 In this question you must show detailed reasoning.
Find the coordinates of the points where the curve \(y = x ^ { 3 } - 2 x ^ { 2 } - 5 x + 6\) crosses the \(x\)-axis.
OCR MEI Further Pure Core AS 2023 June Q3
6 marks Standard +0.3
3 In this question you must show detailed reasoning.
The function \(\mathrm { f } ( \mathrm { z } )\) is given by \(\mathrm { f } ( \mathrm { z } ) = 2 \mathrm { z } ^ { 3 } - 7 \mathrm { z } ^ { 2 } + 16 \mathrm { z } - 15\).
By first evaluating \(\mathrm { f } \left( \frac { 3 } { 2 } \right)\), find the roots of \(\mathrm { f } ( \mathrm { z } ) = 0\).
WJEC Unit 3 2022 June Q10
Moderate -0.5
Solve the equation $$\frac { 6 x ^ { 5 } - 17 x ^ { 4 } - 5 x ^ { 3 } + 6 x ^ { 2 } } { ( 3 x + 2 ) } = 0$$
WJEC Unit 1 2019 June Q03
6 marks Standard +0.3
Use an algebraic method to solve the equation \(12x^3 - 29x^2 + 7x + 6 = 0\). Show all your working. [6]
WJEC Unit 1 2022 June Q12
9 marks Moderate -0.3
  1. Solve the equation \(2x^3 - x^2 - 5x - 2 = 0\). [6]
  2. Find all values of \(\theta\) in the range \(0° < \theta < 180°\) satisfying $$\cos(2\theta - 51°) = 0.891.$$ [3]