Two girls, Marie and Nina, are members of an Olympic hockey team. They are doing fitness training.
Marie runs along a straight line at a constant speed of \(6\) ms\(^{-1}\).
Nina is stationary at a point O on the line until Marie passes her. Nina immediately runs after Marie until she catches up with her.
The time, \(t\) s, is measured from the moment when Nina starts running. So when \(t = 0\), both girls are at O.
Nina's acceleration, \(a\) ms\(^{-2}\), is given by
\begin{align}
a &= 4 - t \quad \text{for } 0 < t < 4,
a &= 0 \quad \text{for } t > 4.
\end{align}
- Show that Nina's speed, \(v\) ms\(^{-1}\), is given by
\begin{align}
v &= 4t - \frac{1}{2}t^2 \quad \text{for } 0 < t < 4,
v &= 8 \quad \text{for } t > 4.
\end{align} [3] - Find an expression for the distance Nina has run at time \(t\), for \(0 \leqslant t < 4\).
Find how far Nina has run when \(t = 4\) and when \(t = 5\frac{1}{4}\). [4]
- Show that Nina catches up with Marie when \(t = 5\frac{1}{4}\). [1]