Numerical gradient deduction

A question is this type if and only if it provides a table or list of chord gradients for decreasing values of h and asks students to deduce or estimate the gradient at a point from the pattern.

3 questions · Moderate -0.5

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CAIE P1 2021 June Q3
4 marks Easy -1.2
3 The equation of a curve is \(y = ( x - 3 ) \sqrt { x + 1 } + 3\). The following points lie on the curve. Non-exact values are rounded to 4 decimal places. $$A ( 2 , k ) \quad B ( 2.9,2.8025 ) \quad C ( 2.99,2.9800 ) \quad D ( 2.999,2.9980 ) \quad E ( 3,3 )$$
  1. Find \(k\), giving your answer correct to 4 decimal places.
  2. Find the gradient of \(A E\), giving your answer correct to 4 decimal places.
    The gradients of \(B E , C E\) and \(D E\), rounded to 4 decimal places, are 1.9748, 1.9975 and 1.9997 respectively.
  3. State, giving a reason for your answer, what the values of the four gradients suggest about the gradient of the curve at the point \(E\).
CAIE P1 2020 Specimen Q1
3 marks Easy -1.2
1 The following points $$A ( 0,1 ) , \quad B ( 1,6 ) , \quad C ( 1.5,7.75 ) , \quad D ( 1.9,8.79 ) \quad \text { and } \quad E ( 2,9 )$$ lie on the curve \(y = \mathrm { f } ( x )\). The table below shows the gradients of the chords \(A E\) and \(B E\).
Chord\(A E\)\(B E\)\(C E\)\(D E\)
Gradient of
chord
43
  1. Complete the table to show the gradients of \(C E\) and \(D E\).
  2. State what the values in the table indicate about the value of \(\mathrm { f } ^ { \prime } ( 2 )\).
OCR MEI Further Numerical Methods 2019 June Q5
12 marks Standard +0.8
5 Fig. 5 shows spreadsheet output concerning the estimation of the derivative of a function \(\mathrm { f } ( x )\) at \(x = 2\) using the forward difference method. \begin{table}[h]
ABCD
1hestimatedifferenceratio
20.16.3050005
30.016.0300512-0.274949
40.0016.0030018-0.0270490.098379
50.00016.0003014-0.00270.099835
60.000016.0000314-0.000270.099983
70.0000016.0000044\(- 2.7 \mathrm { E } - 05\)0.099994
81E-076.0000016\(- 2.71 \mathrm { E } - 06\)0.100352
91E-086.0000013\(- 3.02 \mathrm { E } - 07\)0.111457
101E-096.0000018\(4.885 \mathrm { E } - 07\)-1.61765
111E-106.0000049\(3.109 \mathrm { E } - 06\)6.363636
121E-116.0000005\(- 4.44 \mathrm { E } - 06\)-1.42857
131E-126.00053340.0005329-120
141E-135.9952043-0.005329-10
151E-146.12843110.1332268-25
161E-155.3290705-0.799361-6
171E-160-5.3290716.666667
\captionsetup{labelformat=empty} \caption{Fig. 5}
\end{table}
  1. Write down suitable cell formulae for
    The formula in cell B2 is \(\quad = ( \mathrm { LN } ( \mathrm { SQRT } ( \mathrm { SINH } ( ( 2 + \mathrm { A } 2 ) \wedge 3 ) ) ) - \mathrm { LN } ( \mathrm { SQRT } ( \mathrm { SINH } ( 2 \wedge 3 ) ) ) ) / \mathrm { A } 2\) and equivalent formulae are entered in cells B3 to B17.
  2. Write \(\mathrm { f } ( x )\) in standard mathematical notation. The value displayed in cell B17 is zero, even though the calculation results in a non-zero answer.
  3. Explain how this has arisen.