The random variable \(X\) has probability density function
$$f(x) = 1 + \frac{3\lambda x}{2} \quad \text{for } -\frac{1}{2} \leqslant x \leqslant \frac{1}{2},$$
$$f(x) = 0 \quad \text{otherwise,}$$
where \(\lambda\) is an unknown parameter such that \(-1 \leqslant \lambda \leqslant 1\).
- Find E\((X)\) in terms of \(\lambda\).
- Show that \(\text{Var}(X) = \frac{16 - 3\lambda^2}{192}\). [6]
- Show that P\((X > 0) = \frac{8 + 3\lambda}{16}\). [2]
In order to estimate \(\lambda\), \(n\) independent observations of \(X\) are made. The number of positive observations obtained is denoted by \(Y\) and the sample mean is denoted by \(\overline{X}\).
- Identify the distribution of \(Y\).
- Show that \(T_1\) is an unbiased estimator for \(\lambda\), where
$$T_1 = \frac{16Y}{3n} - \frac{8}{3}.$$ [4]
- Show that \(\text{Var}(T_1) = \frac{64 - 9\lambda^2}{9n}\).
- Given that \(T_2\) is also an unbiased estimator for \(\lambda\), where
$$T_2 = 8\overline{X},$$
find an expression for Var\((T_2)\) in terms of \(\lambda\) and \(n\).
- Hence, giving a reason, determine which is the better estimator, \(T_1\) or \(T_2\). [6]