4.10c Integrating factor: first order equations

217 questions

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AQA Further Paper 1 2019 June Q11
7 marks Challenging +1.2
Find the general solution of the differential equation $$x \frac{dy}{dx} - 2y = \frac{x^3}{\sqrt{4 - 2x - x^2}}$$ where \(0 < x < \sqrt{5} - 1\) [7 marks]
AQA Further Paper 1 2024 June Q14
7 marks Challenging +1.2
Solve the differential equation $$\frac{dy}{dx} + y\tanh x = \sinh^3 x$$ given that \(y = 3\) when \(x = \ln 2\) Give your answer in an exact form. [7 marks]
AQA Further Paper 1 Specimen Q6
7 marks Standard +0.8
  1. Obtain the general solution of the differential equation $$\tan x \frac{dy}{dx} + y = \sin x \tan x$$ where \(0 < x < \frac{\pi}{2}\) [5 marks]
  2. Hence find the particular solution of this differential equation, given that \(y = \frac{1}{2\sqrt{2}}\) when \(x = \frac{\pi}{4}\) [2 marks]
AQA Further Paper 2 2020 June Q12
12 marks Challenging +1.3
  1. Given that \(I = \int_a^b e^{2t} \sin t \, dt\), show that $$I = \left[ qe^{2t} \sin t + re^{2t} \cos t \right]_a^b$$ where \(q\) and \(r\) are rational numbers to be found. [6 marks]
  2. A small object is initially at rest. The subsequent motion of the object is modelled by the differential equation $$\frac{dv}{dt} + v = 5e^t \sin t$$ where \(v\) is the velocity at time \(t\). Find the speed of the object when \(t = 2\pi\), giving your answer in exact form. [6 marks]
Edexcel CP1 2021 June Q8
9 marks Standard +0.3
Two different colours of paint are being mixed together in a container. The paint is stirred continuously so that each colour is instantly dispersed evenly throughout the container. Initially the container holds a mixture of 10 litres of red paint and 20 litres of blue paint. The colour of the paint mixture is now altered by
  • adding red paint to the container at a rate of 2 litres per second
  • adding blue paint to the container at a rate of 1 litre per second
  • pumping fully mixed paint from the container at a rate of 3 litres per second.
Let \(r\) litres be the amount of red paint in the container at time \(t\) seconds after the colour of the paint mixture starts to be altered.
  1. Show that the amount of red paint in the container can be modelled by the differential equation $$\frac{dr}{dt} = 2 - \frac{r}{a}$$ where \(a\) is a positive constant to be determined. [2]
  2. By solving the differential equation, determine how long it will take for the mixture of paint in the container to consist of equal amounts of red paint and blue paint, according to the model. Give your answer to the nearest second. [6] It actually takes 9 seconds for the mixture of paint in the container to consist of equal amounts of red paint and blue paint.
  3. Use this information to evaluate the model, giving a reason for your answer. [1]
OCR MEI Further Pure Core Specimen Q10
9 marks Standard +0.8
  1. Obtain the solution to the differential equation $$x \frac{dy}{dx} + 3y = \frac{1}{x}, \text{ where } x > 0,$$ given that \(y = 1\) when \(x = 1\). [7]
  2. Deduce that \(y\) decreases as \(x\) increases. [2]
WJEC Further Unit 4 2019 June Q10
8 marks Challenging +1.8
Given the differential equation $$\sec x \frac{\mathrm{d}y}{\mathrm{d}x} + y\cos \sec x = 2$$ and \(x = \frac{\pi}{2}\) when \(y = 3\), find the value of \(y\) when \(x = \frac{\pi}{4}\). [8]
WJEC Further Unit 4 2023 June Q9
8 marks Standard +0.8
Consider the differential equation $$\left(x+1\right)\frac{\mathrm{d}y}{\mathrm{d}x} + 5y = (x+1)^2, \quad x > -1.$$ Given that \(y = \frac{1}{4}\) when \(x = 1\), find the value of \(y\) when \(x = 0\). [8]
WJEC Further Unit 4 2024 June Q3
9 marks Challenging +1.2
Given the differential equation $$\cos x \frac{\mathrm{d}y}{\mathrm{d}x} + y \sin x = 4 \cos^2 x \sin x + 5$$ and \(y = 3\sqrt{2}\) when \(x = \frac{\pi}{4}\), find an equation for \(y\) in terms of \(x\). [9]
WJEC Further Unit 4 Specimen Q10
11 marks Standard +0.8
Consider the differential equation $$\frac{dy}{dx} + 2y \tan x = \sin x, \quad 0 < x < \frac{\pi}{2}.$$
  1. Find an integrating factor for this differential equation. [4]
  2. Solve the differential equation given that \(y = 0\) when \(x = \frac{\pi}{4}\), giving your answer in the form \(y = f(x)\). [7]
SPS SPS FM Pure 2021 May Q10
7 marks Standard +0.8
A particular radioactive substance decays over time. A scientist models the amount of substance, \(x\) grams, at time \(t\) hours by the differential equation $$\frac{dx}{dt} + \frac{1}{10}x = e^{-0.1t}\cos t.$$
  1. Solve the differential equation to find the general solution for \(x\) in terms of \(t\). [3]
Initially there was \(10\) g of the substance.
  1. Find the particular solution of the differential equation. [2]
  2. Find to \(6\) significant figures the amount of substance that would be predicted by the model at
    1. \(6\) hours, [1]
    2. \(6.25\) hours. [1]
SPS SPS FM Pure 2022 February Q11
12 marks Challenging +1.2
A particle \(P\) of mass 2 kg can only move along the straight line segment \(OA\), where \(OA\) is on a rough horizontal surface. The particle is initially at rest at \(O\) and the distance \(OA\) is 0.9 m. When the time is \(t\) seconds the displacement of \(P\) from \(O\) is \(x\) m and the velocity of \(P\) is \(v\) ms\(^{-1}\). \(P\) is subject to a force of magnitude \(4e^{-2t}\) N in the direction of \(A\) for any \(t \geqslant 0\). The resistance to the motion of \(P\) is modelled as being proportional to \(v\). At the instant when \(t = \ln 2\), \(v = 0.5\) and the resultant force on \(P\) is 0 N.
  1. Show that, according to the model, \(\frac{dv}{dt} + v = 2e^{-2t}\). [3]
  2. Find an expression for \(v\) in terms of \(t\) for \(t \geqslant 0\). [5]
  3. By considering the behaviour of \(v\) as \(t\) becomes large explain why, according to the model, \(P\)'s speed must reach a maximum value for some \(t > 0\). [2]
  4. Determine the maximum speed considered in part (c). [2]
SPS SPS FM Pure 2023 February Q10
10 marks Challenging +1.3
  1. Find the general solution of the differential equation $$\frac{dy}{dx} + \frac{2y}{x} = \frac{x+3}{x(x-1)(x^2+3)} \quad (x > 1)$$ [8]
  2. Find the particular solution for which \(y = 0\) when \(x = 3\). Give your answer in the form \(y = f(x)\). [2]
SPS SPS FM Pure 2024 February Q12
7 marks Challenging +1.2
Find the general solution of the differential equation $$x\frac{dy}{dx} - 2y = \frac{x^3}{\sqrt{4 - 2x - x^2}}$$ where \(0 < x < \sqrt{5} - 1\) [7 marks]
SPS SPS FM Pure 2025 February Q12
11 marks Challenging +1.8
The population density \(P\), in suitable units, of a certain bacterium at time \(t\) hours is to be modelled by a differential equation. Initially, the population density is zero, and its long-term value is 5. The model uses the differential equation $$\frac{dP}{dt} - \frac{P}{t(1 + t^2)} = \frac{te^{-t}}{\sqrt{1 + t^2}}$$ Find \(P\) as a function of \(t\). [You may assume that \(\lim_{t \to \infty} te^{-t} = 0\)]. [11]
Pre-U Pre-U 9795/1 2013 November Q11
14 marks Standard +0.8
  1. Given that \(y = -4\) when \(x = 0\) and that $$\frac{dy}{dx} - y = e^{2x} + 3,$$ find the value of \(x\) for which \(y = 0\). [7]
  2. Find the general solution of $$\frac{d^2y}{dx^2} - 4\frac{dy}{dx} + 4y = e^{2x} + 3,$$ given that \(y = cx^2e^{2x} + d\) is a suitable form of particular integral. [7]
Pre-U Pre-U 9795/1 2018 June Q5
8 marks Standard +0.8
Find, in the form \(y = f(x)\), the solution of the differential equation \(\frac{dy}{dx} + y\tanh x = 2\cosh x\), given that \(y = \frac{3}{4}\) when \(x = \ln 2\). [8]