CAIE P1 2012 November — Question 4 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2012
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeBinomial times linear coefficient
DifficultyModerate -0.3 This is a straightforward binomial expansion question requiring standard application of the binomial theorem followed by a simple multiplication. Part (i) is routine calculation, and part (ii) only requires identifying which terms from part (i) contribute to x^8 after multiplying by (2+x). Slightly easier than average due to the mechanical nature and clear structure, though the algebraic manipulation keeps it from being trivial.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

4
  1. Find the first 3 terms in the expansion of \(\left( 2 x - x ^ { 2 } \right) ^ { 6 }\) in ascending powers of \(x\).
  2. Hence find the coefficient of \(x ^ { 8 }\) in the expansion of \(( 2 + x ) \left( 2 x - x ^ { 2 } \right) ^ { 6 }\).

AnswerMarks Guidance
(i) \((2x - x^2)^6 = 64x^6 - 192x^7 + 240x^8\)B1B1B1 cao
(ii) \(\times(2 + x)\) coeff of \(x^8 = 2x \cdot 240 - 192 \cdot 288\)M1 Looks at exactly 2 terms
A1[2]
**(i)** $(2x - x^2)^6 = 64x^6 - 192x^7 + 240x^8$ | B1B1B1 | cao | [3]

**(ii)** $\times(2 + x)$ coeff of $x^8 = 2x \cdot 240 - 192 \cdot 288$ | M1 | Looks at exactly 2 terms
| A1 | [2]
4 (i) Find the first 3 terms in the expansion of $\left( 2 x - x ^ { 2 } \right) ^ { 6 }$ in ascending powers of $x$.\\
(ii) Hence find the coefficient of $x ^ { 8 }$ in the expansion of $( 2 + x ) \left( 2 x - x ^ { 2 } \right) ^ { 6 }$.

\hfill \mbox{\textit{CAIE P1 2012 Q4 [5]}}