Edexcel P3 2020 October — Question 1 5 marks

Exam BoardEdexcel
ModuleP3 (Pure Mathematics 3)
Year2020
SessionOctober
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeSolve equation with sin2x/cos2x by substitution
DifficultyModerate -0.3 This is a straightforward double angle equation requiring the standard substitution cos(2x) = 2cos²(x) - 1, leading to a quadratic in cos(x). The algebraic manipulation is routine, and finding solutions in the given range is standard A-level technique. Slightly easier than average due to its predictable structure and limited steps.
Spec1.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

  1. Solve, for \(0 \leqslant x < 360 ^ { \circ }\), the equation
$$2 \cos 2 x = 7 \cos x$$ giving your solutions to one decimal place.
(Solutions based entirely on graphical or numerical methods are not acceptable.)

\(2\cos 2x - 1 = 7\cos x\) M1
\(4\cos^2 x - 7\cos x - 2 = 0 \Rightarrow \cos x = -\frac{1}{4}\) M1 A1
\(x = \arccos\left(-\frac{1}{4}\right) = 104.5°, 255.5°\) dM1 A1
(5 marks)
$2\cos 2x - 1 = 7\cos x$ M1

$4\cos^2 x - 7\cos x - 2 = 0 \Rightarrow \cos x = -\frac{1}{4}$ M1 A1

$x = \arccos\left(-\frac{1}{4}\right) = 104.5°, 255.5°$ dM1 A1

(5 marks)
\begin{enumerate}
  \item Solve, for $0 \leqslant x < 360 ^ { \circ }$, the equation
\end{enumerate}

$$2 \cos 2 x = 7 \cos x$$

giving your solutions to one decimal place.\\
(Solutions based entirely on graphical or numerical methods are not acceptable.)\\

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\hfill \mbox{\textit{Edexcel P3 2020 Q1 [5]}}