Edexcel P3 2021 June — Question 5 7 marks

Exam BoardEdexcel
ModuleP3 (Pure Mathematics 3)
Year2021
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Equations & Modelling
TypeCalculus with exponential models
DifficultyStandard +0.3 This is a standard exponential modelling question requiring logarithmic manipulation to find constants (using two points on a line) and then differentiation of an exponential function. All techniques are routine for P3/C3 level with clear scaffolding through parts (a) and (b). Slightly easier than average due to straightforward application of well-practiced methods.
Spec1.06h Logarithmic graphs: reduce y=ax^n and y=kb^x to linear form1.06i Exponential growth/decay: in modelling context1.07k Differentiate trig: sin(kx), cos(kx), tan(kx)

5. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{76205772-5395-4ab2-96f9-ad9803b8388c-16_582_737_248_607} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} The growth of duckweed on a pond is being studied. The surface area of the pond covered by duckweed, \(A \mathrm {~m} ^ { 2 }\), at a time \(t\) days after the start of the study is modelled by the equation $$A = p q ^ { t } \quad \text { where } p \text { and } q \text { are positive constants }$$ Figure 1 shows the linear relationship between \(\log _ { 10 } A\) and \(t\).
The points \(( 0,0.32 )\) and \(( 8,0.56 )\) lie on the line as shown.
  1. Find, to 3 decimal places, the value of \(p\) and the value of \(q\). Using the model with the values of \(p\) and \(q\) found in part (a),
  2. find the rate of increase of the surface area of the pond covered by duckweed, in \(\mathrm { m } ^ { 2 }\) / day, exactly 6 days after the start of the study.
    Give your answer to 2 decimal places. \includegraphics[max width=\textwidth, alt={}, center]{76205772-5395-4ab2-96f9-ad9803b8388c-19_2649_1840_117_114}

Question 5:
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
States or implies \(\log_{10} p = 0.32\) or \(\log_{10} q = \frac{0.56 - 0.32}{8}\)M1 Or equivalent equations
\(p =\) awrt \(2.089\) or \(q =\) awrt \(1.072\)A1
States or implies \(\log_{10} p = 0.32\) and \(\log_{10} q = \frac{0.56 - 0.32}{8}\)M1 Or equivalent equations
\(p =\) awrt \(2.089\) and \(q =\) awrt \(1.072\)A1
(4 marks)
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
States or implies \(\frac{dA}{dt} = p \ln q \times q^t\) with their values for \(p\) and \(q\)M1 A1 Uses \(\frac{d}{dt}q^t \rightarrow kq^t\), \(k \neq 1\)
Rate of increase in pond weed after 6 days is \(0.22\) (m²/day)A1 Units not required
(3 marks)
Alt (b): Using \(\log_{10} A = 0.03t + 0.32\) as starting point:
AnswerMarks Guidance
Answer/WorkingMark Guidance
Attempts to differentiate and reaches \(\frac{1}{A}\frac{dA}{dt} = k\)M1 Or equivalent
\(\frac{1}{A \ln 10}\frac{dA}{dt} = 0.03\)A1
awrt \(0.22\)A1 Units not required
## Question 5:

### Part (a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| States or implies $\log_{10} p = 0.32$ **or** $\log_{10} q = \frac{0.56 - 0.32}{8}$ | M1 | Or equivalent equations |
| $p =$ awrt $2.089$ **or** $q =$ awrt $1.072$ | A1 | |
| States or implies $\log_{10} p = 0.32$ **and** $\log_{10} q = \frac{0.56 - 0.32}{8}$ | M1 | Or equivalent equations |
| $p =$ awrt $2.089$ **and** $q =$ awrt $1.072$ | A1 | |

**(4 marks)**

### Part (b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| States or implies $\frac{dA}{dt} = p \ln q \times q^t$ with their values for $p$ and $q$ | M1 A1 | Uses $\frac{d}{dt}q^t \rightarrow kq^t$, $k \neq 1$ |
| Rate of increase in pond weed after 6 days is $0.22$ (m²/day) | A1 | Units not required |

**(3 marks)**

**Alt (b):** Using $\log_{10} A = 0.03t + 0.32$ as starting point:

| Answer/Working | Mark | Guidance |
|---|---|---|
| Attempts to differentiate and reaches $\frac{1}{A}\frac{dA}{dt} = k$ | M1 | Or equivalent |
| $\frac{1}{A \ln 10}\frac{dA}{dt} = 0.03$ | A1 | |
| awrt $0.22$ | A1 | Units not required |

---
5.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{76205772-5395-4ab2-96f9-ad9803b8388c-16_582_737_248_607}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

The growth of duckweed on a pond is being studied.

The surface area of the pond covered by duckweed, $A \mathrm {~m} ^ { 2 }$, at a time $t$ days after the start of the study is modelled by the equation

$$A = p q ^ { t } \quad \text { where } p \text { and } q \text { are positive constants }$$

Figure 1 shows the linear relationship between $\log _ { 10 } A$ and $t$.\\
The points $( 0,0.32 )$ and $( 8,0.56 )$ lie on the line as shown.
\begin{enumerate}[label=(\alph*)]
\item Find, to 3 decimal places, the value of $p$ and the value of $q$.

Using the model with the values of $p$ and $q$ found in part (a),
\item find the rate of increase of the surface area of the pond covered by duckweed, in $\mathrm { m } ^ { 2 }$ / day, exactly 6 days after the start of the study.\\
Give your answer to 2 decimal places.\\

\includegraphics[max width=\textwidth, alt={}, center]{76205772-5395-4ab2-96f9-ad9803b8388c-19_2649_1840_117_114}
\end{enumerate}

\hfill \mbox{\textit{Edexcel P3 2021 Q5 [7]}}