Edexcel P3 2023 January — Question 8 5 marks

Exam BoardEdexcel
ModuleP3 (Pure Mathematics 3)
Year2023
SessionJanuary
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeUse trig identity before indefinite integration
DifficultyModerate -0.8 This question requires expanding the squared bracket to get standard trigonometric terms, then applying the double angle formula for cos²x and integrating standard forms. It's a routine multi-step question testing algebraic manipulation and standard integral knowledge, but more straightforward than average A-level questions since the techniques are well-practiced and the path is clear once expanded.
Spec1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)

  1. Find, in simplest form,
$$\int ( 2 \cos x - \sin x ) ^ { 2 } d x$$

Question 8:
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\int(2\cos x - \sin x)^2\,dx = \int\left(4\cos^2 x - 4\sin x\cos x + \sin^2 x\right)dx\)M1 Expands to form \(p\cos^2 x + q\sin x\cos x + r\sin^2 x\)
\(\int 4\sin x\cos x\,dx = \int 2\sin 2x\,dx = -\cos 2x\) or \(-2\cos^2 x\) or \(2\sin^2 x\)M1 Correct strategy for integrating \(q\sin x\cos x\), obtaining \(k\cos 2x\) or \(k\sin^2 x\) or \(k\cos^2 x\)
\(\int\left(4\cos^2 x+\sin^2 x\right)dx = \int\left(1+3\cos^2 x\right)dx = \int\left(1+3\left(\frac{\cos 2x+1}{2}\right)\right)dx\)M1 Correct strategy for rewriting \(p\cos^2 x + r\sin^2 x\) into a form that can be integrated. Uses \(\sin^2 x = \frac{\pm1\pm\cos 2x}{2}\) or \(\cos^2 x = \frac{\pm1\pm\cos 2x}{2}\)
\(\int(2\cos x-\sin x)^2\,dx = \frac{3}{4}\sin 2x + \cos 2x + \frac{5}{2}x\ (+c)\)A1 Integrates and achieves 2 correct terms (of 3 required terms). Unsimplified expressions acceptable
or \(\frac{3}{4}\sin 2x + 2\cos^2 x + \frac{5}{2}x\ (+c)\) or \(\frac{3}{4}\sin 2x - 2\sin^2 x + \frac{5}{2}x\ (+c)\)A1 Correct simplified integration (\(+c\) not required)
## Question 8:

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\int(2\cos x - \sin x)^2\,dx = \int\left(4\cos^2 x - 4\sin x\cos x + \sin^2 x\right)dx$ | M1 | Expands to form $p\cos^2 x + q\sin x\cos x + r\sin^2 x$ |
| $\int 4\sin x\cos x\,dx = \int 2\sin 2x\,dx = -\cos 2x$ or $-2\cos^2 x$ or $2\sin^2 x$ | M1 | Correct strategy for integrating $q\sin x\cos x$, obtaining $k\cos 2x$ or $k\sin^2 x$ or $k\cos^2 x$ |
| $\int\left(4\cos^2 x+\sin^2 x\right)dx = \int\left(1+3\cos^2 x\right)dx = \int\left(1+3\left(\frac{\cos 2x+1}{2}\right)\right)dx$ | M1 | Correct strategy for rewriting $p\cos^2 x + r\sin^2 x$ into a form that can be integrated. Uses $\sin^2 x = \frac{\pm1\pm\cos 2x}{2}$ or $\cos^2 x = \frac{\pm1\pm\cos 2x}{2}$ |
| $\int(2\cos x-\sin x)^2\,dx = \frac{3}{4}\sin 2x + \cos 2x + \frac{5}{2}x\ (+c)$ | A1 | Integrates and achieves 2 correct terms (of 3 required terms). Unsimplified expressions acceptable |
| or $\frac{3}{4}\sin 2x + 2\cos^2 x + \frac{5}{2}x\ (+c)$ or $\frac{3}{4}\sin 2x - 2\sin^2 x + \frac{5}{2}x\ (+c)$ | A1 | Correct simplified integration ($+c$ not required) |
\begin{enumerate}
  \item Find, in simplest form,
\end{enumerate}

$$\int ( 2 \cos x - \sin x ) ^ { 2 } d x$$

\hfill \mbox{\textit{Edexcel P3 2023 Q8 [5]}}