Edexcel C2 2005 June — Question 1 4 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Year2005
SessionJune
Marks4
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TopicStationary points and optimisation
TypeFind stationary points coordinates
DifficultyEasy -1.2 This is a straightforward C2 differentiation question requiring only basic power rule differentiation and solving a linear equation. It's simpler than average A-level questions as it involves no complications like product/quotient rules, determining nature of stationary points, or multi-step problem-solving—just routine application of dy/dx = 0.
Spec1.07n Stationary points: find maxima, minima using derivatives
Find the coordinates of the stationary point on the curve with equation \(y = 2 x ^ { 2 } - 12 x\).
Question 1:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\frac{dy}{dx} = 4x - 12\)B1
\(4x - 12 = 0 \Rightarrow x = 3\)M1 A1ft Equate \(\frac{dy}{dx}\) (not just \(y\)) to zero and proceed to \(x = \ldots\); A1ft follow through only from a linear equation in \(x\)
\(y = -18\)A1 Total: 4 
## Question 1:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\frac{dy}{dx} = 4x - 12$ | B1 | |
| $4x - 12 = 0 \Rightarrow x = 3$ | M1 A1ft | Equate $\frac{dy}{dx}$ (not just $y$) to zero and proceed to $x = \ldots$; A1ft follow through only from a linear equation in $x$ |
| $y = -18$ | A1 | **Total: 4** |

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Find the coordinates of the stationary point on the curve with equation $y = 2 x ^ { 2 } - 12 x$.\\

\hfill \mbox{\textit{Edexcel C2 2005 Q1 [4]}}
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Q1 4 Q2 6 Q3 6 Q4 6 Q5 8 Q6 8 Q7 6 Q8 9 Q9 10 Q10 12