Edexcel C2 2013 January — Question 6 7 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Year2013
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLaws of Logarithms
TypeSolve by showing reduces to polynomial
DifficultyModerate -0.3 This is a straightforward logarithm question requiring standard laws of logs (combining logs, power rule) and solving a quadratic. Part (a) is scaffolded to guide students to the polynomial form, and part (b) requires only factorization or the quadratic formula plus checking validity. Slightly easier than average due to the scaffolding and routine application of techniques.
Spec1.02f Solve quadratic equations: including in a function of unknown1.06f Laws of logarithms: addition, subtraction, power rules1.06g Equations with exponentials: solve a^x = b

6. Given that $$2 \log _ { 2 } ( x + 15 ) - \log _ { 2 } x = 6$$
  1. Show that $$x ^ { 2 } - 34 x + 225 = 0$$
  2. Hence, or otherwise, solve the equation $$2 \log _ { 2 } ( x + 15 ) - \log _ { 2 } x = 6$$

Question 6:
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(2\log(x+15) = \log(x+15)^2\)B1
\(\log(x+15)^2 - \log x = \log\dfrac{(x+15)^2}{x}\)M1 Correct use of \(\log a - \log b = \log\dfrac{a}{b}\)
\(2^6 = 64\) or \(\log_2 64 = 6\)B1 64 used in the correct context
\(\log_2\dfrac{(x+15)^2}{x} = 6 \Rightarrow \dfrac{(x+15)^2}{x} = 64\)M1 Removes logs correctly
\(x^2 + 30x + 225 = 64x\) or \(x + 30 + 225x^{-1} = 64\) Must see expansion of \((x+15)^2\) to score the final mark
\(x^2 - 34x + 225 = 0\)A1
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\((x-25)(x-9) = 0 \Rightarrow x = 25\) or \(x = 9\)M1 A1 M1: Correct attempt to solve the given quadratic as far as \(x = \ldots\); A1: Both 25 and 9
## Question 6:

### Part (a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $2\log(x+15) = \log(x+15)^2$ | B1 | |
| $\log(x+15)^2 - \log x = \log\dfrac{(x+15)^2}{x}$ | M1 | Correct use of $\log a - \log b = \log\dfrac{a}{b}$ |
| $2^6 = 64$ or $\log_2 64 = 6$ | B1 | 64 used in the correct context |
| $\log_2\dfrac{(x+15)^2}{x} = 6 \Rightarrow \dfrac{(x+15)^2}{x} = 64$ | M1 | Removes logs correctly |
| $x^2 + 30x + 225 = 64x$ or $x + 30 + 225x^{-1} = 64$ | | Must see expansion of $(x+15)^2$ to score the final mark |
| $x^2 - 34x + 225 = 0$ | A1 | |

### Part (b):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $(x-25)(x-9) = 0 \Rightarrow x = 25$ or $x = 9$ | M1 A1 | M1: Correct attempt to solve the given quadratic as far as $x = \ldots$; A1: Both 25 and 9 |
6. Given that

$$2 \log _ { 2 } ( x + 15 ) - \log _ { 2 } x = 6$$
\begin{enumerate}[label=(\alph*)]
\item Show that

$$x ^ { 2 } - 34 x + 225 = 0$$
\item Hence, or otherwise, solve the equation

$$2 \log _ { 2 } ( x + 15 ) - \log _ { 2 } x = 6$$
\end{enumerate}

\hfill \mbox{\textit{Edexcel C2 2013 Q6 [7]}}