- (a) Show that the equation
$$3 \sin ^ { 2 } x + 7 \sin x = \cos ^ { 2 } x - 4$$
can be written in the form
$$4 \sin ^ { 2 } x + 7 \sin x + 3 = 0$$
(b) Hence solve, for \(0 \leqslant x < 360 ^ { \circ }\),
$$3 \sin ^ { 2 } x + 7 \sin x = \cos ^ { 2 } x - 4$$
giving your answers to 1 decimal place where appropriate.