Edexcel C2 2005 January — Question 7 11 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Year2005
SessionJanuary
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRadians, Arc Length and Sector Area
TypeTriangle and sector combined - area/perimeter with given values
DifficultyStandard +0.3 This is a straightforward C2 question combining standard arc length formula (s=rθ), cosine rule for finding BC, and area calculations using sector and triangle formulas. All techniques are routine applications with no novel insight required, making it slightly easier than average.
Spec1.05b Sine and cosine rules: including ambiguous case1.05c Area of triangle: using 1/2 ab sin(C)1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

7. \begin{figure}[h]
\captionsetup{labelformat=empty} \caption{Figure 1} \includegraphics[alt={},max width=\textwidth]{13bca882-27da-40f2-99d8-4fdeb6629c4e-12_707_1072_301_434}
\end{figure} Figure 1 shows the triangle \(A B C\), with \(A B = 8 \mathrm {~cm} , A C = 11 \mathrm {~cm}\) and \(\angle B A C = 0.7\) radians. The \(\operatorname { arc } B D\), where \(D\) lies on \(A C\), is an arc of a circle with centre \(A\) and radius 8 cm . The region \(R\), shown shaded in Figure 1, is bounded by the straight lines \(B C\) and \(C D\) and the \(\operatorname { arc } B D\). Find
  1. the length of the \(\operatorname { arc } B D\),
  2. the perimeter of \(R\), giving your answer to 3 significant figures,
  3. the area of \(R\), giving your answer to 3 significant figures.

AnswerMarks Guidance
(a) \(r\theta = 8 \times 0.7 = 5.6\) (cm)M1, A1 (2 marks)
(b) \(BC^2 = 8^2 + 11^2 - 2 \times 8 \times 11 \times \cos 0.7\)
AnswerMarks Guidance
\(\Rightarrow BC = 7.098\) or \(7.10\) (Awrt) or \(\sqrt{(50.4)}\) or betterM1, A1, M1, A1 cao (4 marks)
Perimeter \(= (a) + (11-8) + BC_c = 15.7\) (cm)
(c) \(\triangle = \frac{1}{2}ab\sin c = \frac{1}{2} \times 11 \times 8 \times \sin 0.7\)
Sector \(= \frac{1}{2}r^2\theta = \frac{1}{2} \times 8^2 \times 0.7\)
AnswerMarks Guidance
Area of \(R = 28.345 \ldots - 22.4 = 5.9455 = 5.95\) (cm²)M1, A1, M1, A1, A1 (5 marks)
(Subtotal: 11 marks)
Guidance: (c) Final A1 accept 3sf or better. (a) and (c) M1 for quoting and attempting to use correct formula. (b) 1st M1 for attempting to use cosine rule (formula given).
**(a)** $r\theta = 8 \times 0.7 = 5.6$ (cm) | M1, A1 | (2 marks)

**(b)** $BC^2 = 8^2 + 11^2 - 2 \times 8 \times 11 \times \cos 0.7$
$\Rightarrow BC = 7.098$ or $7.10$ (Awrt) or $\sqrt{(50.4)}$ or better | M1, A1, M1, A1 cao | (4 marks)
Perimeter $= (a) + (11-8) + BC_c = 15.7$ (cm)

**(c)** $\triangle = \frac{1}{2}ab\sin c = \frac{1}{2} \times 11 \times 8 \times \sin 0.7$
Sector $= \frac{1}{2}r^2\theta = \frac{1}{2} \times 8^2 \times 0.7$
Area of $R = 28.345 \ldots - 22.4 = 5.9455 = 5.95$ (cm²) | M1, A1, M1, A1, A1 | (5 marks)

**(Subtotal: 11 marks)**

Guidance: (c) Final A1 accept 3sf or better. (a) and (c) M1 for quoting and attempting to use correct formula. (b) 1st M1 for attempting to use cosine rule (formula given).
7.

\begin{figure}[h]
\begin{center}
\captionsetup{labelformat=empty}
\caption{Figure 1}
  \includegraphics[alt={},max width=\textwidth]{13bca882-27da-40f2-99d8-4fdeb6629c4e-12_707_1072_301_434}
\end{center}
\end{figure}

Figure 1 shows the triangle $A B C$, with $A B = 8 \mathrm {~cm} , A C = 11 \mathrm {~cm}$ and $\angle B A C = 0.7$ radians. The $\operatorname { arc } B D$, where $D$ lies on $A C$, is an arc of a circle with centre $A$ and radius 8 cm . The region $R$, shown shaded in Figure 1, is bounded by the straight lines $B C$ and $C D$ and the $\operatorname { arc } B D$.

Find
\begin{enumerate}[label=(\alph*)]
\item the length of the $\operatorname { arc } B D$,
\item the perimeter of $R$, giving your answer to 3 significant figures,
\item the area of $R$, giving your answer to 3 significant figures.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C2 2005 Q7 [11]}}