- In this question you must show detailed reasoning.
Solutions relying entirely on calculator technology are not acceptable.
- Show that the equation
$$( 3 \cos \theta - \tan \theta ) \cos \theta = 2$$
can be written as
$$3 \sin ^ { 2 } \theta + \sin \theta - 1 = 0$$
- Hence solve for \(- \frac { \pi } { 2 } \leqslant x \leqslant \frac { \pi } { 2 }\)
$$( 3 \cos 2 x - \tan 2 x ) \cos 2 x = 2$$