CAIE P1 2010 November — Question 8 8 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2010
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicChain Rule
TypeOptimization with constraint
DifficultyStandard +0.3 This is a standard optimization problem with a constraint. Part (i) requires setting up a perimeter equation (straightforward). Part (ii) involves substituting to get area as a function of x (routine algebra). Parts (iii-iv) use basic differentiation to find and classify a stationary point. All steps are textbook-standard with no novel insight required, making it slightly easier than average.
Spec1.07n Stationary points: find maxima, minima using derivatives1.07o Increasing/decreasing: functions using sign of dy/dx1.07p Points of inflection: using second derivative

8 \includegraphics[max width=\textwidth, alt={}, center]{73c0c113-8f35-4e7f-ad5d-604602498b71-3_314_803_751_671} The diagram shows a metal plate consisting of a rectangle with sides \(x \mathrm {~cm}\) and \(y \mathrm {~cm}\) and a quarter-circle of radius \(x \mathrm {~cm}\). The perimeter of the plate is 60 cm .
  1. Express \(y\) in terms of \(x\).
  2. Show that the area of the plate, \(A \mathrm {~cm} ^ { 2 }\), is given by \(A = 30 x - x ^ { 2 }\). Given that \(x\) can vary,
  3. find the value of \(x\) at which \(A\) is stationary,
  4. find this stationary value of \(A\), and determine whether it is a maximum or a minimum value.

Question 8:
Part (i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(2x + 2y + \frac{\pi x}{2} = 60\)\(M1\) Linking 60 with sum of at least 4 sides and use of radians
\(\rightarrow y = 30 - x - \frac{\pi x}{4}\)\(A1\) co
Part (ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(A = xy + \frac{\pi x^2}{4}\)
\(= x\!\left(30 - x - \frac{\pi x}{4}\right) + \frac{\pi x^2}{4}\)\(M1\) Subs "\(y\)" into area equation and use \(\frac{1}{2}r^2\theta\)
\(= 30x - x^2\)\(A1\) co
Part (iii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\frac{dA}{dx} = 30 - 2x\) Knowing to differentiate
\(= 0\) when \(x = 15\) cm\(M1\ A1\) Sets differential to \(0\) + solution. co
Part (iv):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Maximum\(M1\ A1\) Any valid method. co
## Question 8:

### Part (i):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $2x + 2y + \frac{\pi x}{2} = 60$ | $M1$ | Linking 60 with sum of at least 4 sides and use of radians |
| $\rightarrow y = 30 - x - \frac{\pi x}{4}$ | $A1$ | co |

### Part (ii):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $A = xy + \frac{\pi x^2}{4}$ | | |
| $= x\!\left(30 - x - \frac{\pi x}{4}\right) + \frac{\pi x^2}{4}$ | $M1$ | Subs "$y$" into area equation and use $\frac{1}{2}r^2\theta$ |
| $= 30x - x^2$ | $A1$ | co |

### Part (iii):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\frac{dA}{dx} = 30 - 2x$ | | Knowing to differentiate |
| $= 0$ when $x = 15$ cm | $M1\ A1$ | Sets differential to $0$ + solution. co |

### Part (iv):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Maximum | $M1\ A1$ | Any valid method. co |

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8\\
\includegraphics[max width=\textwidth, alt={}, center]{73c0c113-8f35-4e7f-ad5d-604602498b71-3_314_803_751_671}

The diagram shows a metal plate consisting of a rectangle with sides $x \mathrm {~cm}$ and $y \mathrm {~cm}$ and a quarter-circle of radius $x \mathrm {~cm}$. The perimeter of the plate is 60 cm .\\
(i) Express $y$ in terms of $x$.\\
(ii) Show that the area of the plate, $A \mathrm {~cm} ^ { 2 }$, is given by $A = 30 x - x ^ { 2 }$.

Given that $x$ can vary,\\
(iii) find the value of $x$ at which $A$ is stationary,\\
(iv) find this stationary value of $A$, and determine whether it is a maximum or a minimum value.

\hfill \mbox{\textit{CAIE P1 2010 Q8 [8]}}