Edexcel C1 2007 January — Question 3 6 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Year2007
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFunction Transformations
TypeAsymptotes after transformation
DifficultyModerate -0.8 This is a straightforward C1 transformation question requiring a vertical translation of a standard reciprocal function, identifying asymptotes (which shift predictably), and finding an axis intercept by substitution. All steps are routine applications of basic transformation rules with no problem-solving insight needed.
Spec1.02o Sketch reciprocal curves: y=a/x and y=a/x^21.02w Graph transformations: simple transformations of f(x)

3. Given that \(\quad \mathrm { f } ( x ) = \frac { 1 } { x } , \quad x \neq 0\),
  1. sketch the graph of \(y = \mathrm { f } ( x ) + 3\) and state the equations of the asymptotes.
  2. Find the coordinates of the point where \(y = \mathrm { f } ( x ) + 3\) crosses a coordinate axis.

(a)
AnswerMarks Guidance
- Shape of \(f(x)\)B1
- Moved up ↑M1
- Asymptotes: \(y = 3\)B1
- \(x = 0\) (Allow "y-axis")B1 (\(y \neq 3\) is B0, \(x \neq 0\) is B0)
Total: 4 marks
AnswerMarks Guidance
(b) \(\frac{1}{x} + 3 = 0\)M1 No variations accepted.
\(x = -\frac{1}{3}\) (or −0.33 …)A1 Decimal answer requires at least 2 d.p.
Total: 2 marks
Overall: 6 marks
Guidance:
- (a) B1: Shape requires both branches and no obvious "overlap" with the asymptotes. The curve may bend away from the asymptote a little at the end. Sufficient curve must be seen to suggest the asymptotic behaviour, both horizontal and vertical.
- M1: Evidence of an upward translation parallel to the y-axis. The shape of the graph can be wrong, but the complete graph (both branches if they have 2 branches) must be translated upwards. This mark can be awarded generously by implication where the graph drawn is an upward translation of another standard curve (but not a straight line).
- The B marks for asymptote equations are independent of the graph. Ignore extra asymptote equations, if seen.
- (b) Correct answer with no working scores both marks. The answer may be seen on the sketch in part (a). Ignore any attempts to find an intersection with the y-axis.
**(a)** 
- Shape of $f(x)$ | B1 |
- Moved up ↑ | M1 |
- Asymptotes: $y = 3$ | B1 |
- $x = 0$ (Allow "y-axis") | B1 | ($y \neq 3$ is B0, $x \neq 0$ is B0)

**Total: 4 marks**

**(b)** $\frac{1}{x} + 3 = 0$ | M1 | No variations accepted.

$x = -\frac{1}{3}$ (or −0.33 …) | A1 | Decimal answer requires at least 2 d.p.

**Total: 2 marks**

**Overall: 6 marks**

**Guidance:**
- (a) B1: Shape requires both branches and no obvious "overlap" with the asymptotes. The curve may bend away from the asymptote a little at the end. Sufficient curve must be seen to suggest the asymptotic behaviour, both horizontal and vertical.
- M1: Evidence of an upward translation parallel to the y-axis. The shape of the graph can be wrong, but the complete graph (both branches if they have 2 branches) must be translated upwards. This mark can be awarded generously by implication where the graph drawn is an upward translation of another standard curve (but not a straight line).
- The B marks for asymptote equations are independent of the graph. Ignore extra asymptote equations, if seen.
- (b) Correct answer with no working scores both marks. The answer may be seen on the sketch in part (a). Ignore any attempts to find an intersection with the y-axis.

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3. Given that $\quad \mathrm { f } ( x ) = \frac { 1 } { x } , \quad x \neq 0$,
\begin{enumerate}[label=(\alph*)]
\item sketch the graph of $y = \mathrm { f } ( x ) + 3$ and state the equations of the asymptotes.
\item Find the coordinates of the point where $y = \mathrm { f } ( x ) + 3$ crosses a coordinate axis.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1 2007 Q3 [6]}}