CAIE Further Paper 4 2023 November — Question 3 8 marks

Exam BoardCAIE
ModuleFurther Paper 4 (Further Paper 4)
Year2023
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicT-tests (unknown variance)
TypePaired sample t-test
DifficultyStandard +0.3 This is a straightforward paired t-test with clear data and standard procedure. Students calculate differences, find mean and standard deviation, then apply the t-test formula with a one-tailed hypothesis at 2.5% level. The only minor complication is testing for a reduction 'by more than 2 units' rather than just a reduction, requiring μ_d > 2 in the null hypothesis setup. This is slightly easier than average as it's a textbook application with no conceptual tricks.
Spec5.03a Continuous random variables: pdf and cdf5.05c Hypothesis test: normal distribution for population mean

3 Scientists are studying the effects of exercise on LDL blood cholesterol levels. Over a three-month period, a large group of people exercised for 20 minutes each day. For a randomly chosen sample of 10 of these people, the LDL blood cholesterol levels were measured at the beginning and the end of the three-month period. The results, measured in suitable units, are as follows.
\cline { 2 - 12 } \multicolumn{1}{c|}{}Person\(A\)\(B\)\(C\)\(D\)\(E\)\(F\)\(G\)\(H\)\(I\)
\multirow{2}{*}{
Cholesterol
level
}
Beginning72841209010213564758088
\cline { 2 - 12 }End64761059210511567757584
  1. Test, at the \(2.5 \%\) significance level, whether there is evidence that the population mean LDL blood cholesterol level has reduced by more than 2 units after the three-month period.
  2. State any assumption that you have made in part (a). \includegraphics[max width=\textwidth, alt={}, center]{b6635fbc-3c9d-4f93-b51a-b1cbd71ddbb1-06_399_1383_269_324} As shown in the diagram, the continuous random variable \(X\) has probability density function f given by $$f ( x ) = \begin{cases} m x & 0 \leqslant x \leqslant 2 \\ \frac { k } { x ^ { 2 } } + c & 2 \leqslant x \leqslant 6 \\ 0 & \text { otherwise } \end{cases}$$ where \(m , k\) and \(c\) are constants.

Question 3(a):
AnswerMarks Guidance
AnswerMarks Guidance
\(H_0: \mu_B - \mu_E = 2\); \(H_1: \mu_B - \mu_E > 2\)B1 May use \(\mu_d\), but must be consistent with direction of differences found
Differences: 8, 8, 15, \(-2\), \(-3\), 20, \(-3\), 0, 5, 4M1 At most 2 errors
\(\sum d = 52\), \(\sum d^2 = 816\), \(s^2 = \frac{1}{9}\left(816 - \frac{52^2}{10}\right) = \frac{2728}{45} = 60.62\)M1 *Their* values but must see 9 and 10 used correctly
\(t = \dfrac{\frac{52}{10} - 2}{\sqrt{\frac{s^2}{10}}}\)M1
\(t = 1.29967\), \(1.30\)A1
Tabular value \(= 2.262\): \(1.30 < 2.262\), accept \(H_0\)M1 Allow 'not significant'
Insufficient evidence to suggest that cholesterol level has reduced by more than 2A1 CWO. Correct conclusion in context, level of uncertainty in language. A0 if hypotheses wrong way round or missing
Total: 7
Question 3(b):
AnswerMarks Guidance
AnswerMarks Guidance
Population differences are normally distributedB1
Total: 1
## Question 3(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $H_0: \mu_B - \mu_E = 2$; $H_1: \mu_B - \mu_E > 2$ | B1 | May use $\mu_d$, but must be consistent with direction of differences found |
| Differences: 8, 8, 15, $-2$, $-3$, 20, $-3$, 0, 5, 4 | M1 | At most 2 errors |
| $\sum d = 52$, $\sum d^2 = 816$, $s^2 = \frac{1}{9}\left(816 - \frac{52^2}{10}\right) = \frac{2728}{45} = 60.62$ | M1 | *Their* values but must see 9 and 10 used correctly |
| $t = \dfrac{\frac{52}{10} - 2}{\sqrt{\frac{s^2}{10}}}$ | M1 | |
| $t = 1.29967$, $1.30$ | A1 | |
| Tabular value $= 2.262$: $1.30 < 2.262$, accept $H_0$ | M1 | Allow 'not significant' |
| Insufficient evidence to suggest that cholesterol level has reduced by more than 2 | A1 | CWO. Correct conclusion in context, level of uncertainty in language. A0 if hypotheses wrong way round or missing |
| **Total: 7** | | |

---

## Question 3(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| **Population differences** are **normally** distributed | B1 | |
| **Total: 1** | | |

---
3 Scientists are studying the effects of exercise on LDL blood cholesterol levels. Over a three-month period, a large group of people exercised for 20 minutes each day. For a randomly chosen sample of 10 of these people, the LDL blood cholesterol levels were measured at the beginning and the end of the three-month period. The results, measured in suitable units, are as follows.

\begin{center}
\begin{tabular}{ | c | l | c | c | c | c | c | c | c | c | c | c | }
\cline { 2 - 12 }
\multicolumn{1}{c|}{} & \multicolumn{1}{c|}{} & Person & $A$ & $B$ & $C$ & $D$ & $E$ & $F$ & $G$ & $H$ & $I$ \\
\hline
\multirow{2}{*}{\begin{tabular}{ c }
Cholesterol \\
level \\
\end{tabular}} & Beginning & 72 & 84 & 120 & 90 & 102 & 135 & 64 & 75 & 80 & 88 \\
\cline { 2 - 12 }
 & End & 64 & 76 & 105 & 92 & 105 & 115 & 67 & 75 & 75 & 84 \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\alph*)]
\item Test, at the $2.5 \%$ significance level, whether there is evidence that the population mean LDL blood cholesterol level has reduced by more than 2 units after the three-month period.
\item State any assumption that you have made in part (a).\\

\includegraphics[max width=\textwidth, alt={}, center]{b6635fbc-3c9d-4f93-b51a-b1cbd71ddbb1-06_399_1383_269_324}

As shown in the diagram, the continuous random variable $X$ has probability density function f given by

$$f ( x ) = \begin{cases} m x & 0 \leqslant x \leqslant 2 \\ \frac { k } { x ^ { 2 } } + c & 2 \leqslant x \leqslant 6 \\ 0 & \text { otherwise } \end{cases}$$

where $m , k$ and $c$ are constants.
\end{enumerate}

\hfill \mbox{\textit{CAIE Further Paper 4 2023 Q3 [8]}}
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