CAIE Further Paper 4 2022 June — Question 3 8 marks

Exam BoardCAIE
ModuleFurther Paper 4 (Further Paper 4)
Year2022
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProbability Generating Functions
TypeSolve for parameters using PGF coefficients
DifficultyChallenging +1.2 This is a standard PGF question requiring setup of the generating function from a probability distribution, solving simultaneous equations from coefficients, and applying standard PGF properties (composition for sums, variance from derivatives). While it involves Further Maths content, the techniques are routine applications of PGF theory with straightforward algebra—no novel insight required.
Spec5.01a Permutations and combinations: evaluate probabilities

3 George throws two coins, \(A\) and \(B\), at the same time. Coin \(A\) is biased so that the probability of obtaining a head is \(a\). Coin \(B\) is biased so that the probability of obtaining a head is \(b\), where \(\mathrm { b } < \mathrm { a }\). The probability generating function of \(X\), the number of heads obtained by George, is \(\mathrm { G } _ { \mathrm { X } } ( \mathrm { t } )\). The coefficients of \(t\) and \(t ^ { 2 }\) in \(\mathrm { G } _ { \mathrm { X } } ( \mathrm { t } )\) are \(\frac { 5 } { 12 }\) and \(\frac { 1 } { 12 }\) respectively.
  1. Find the value of \(a\).
    The random variable \(Y\) is the sum of two independent observations of \(X\).
  2. Find the probability generating function of \(Y\), giving your answer as a polynomial in \(t\).
  3. Find \(\operatorname { Var } ( Y )\).

Question 3(a):
AnswerMarks Guidance
AnswerMarks Guidance
\(G_X(t) = \frac{6}{12} + \frac{5}{12}t + \frac{1}{12}t^2\); \(P(\text{0 heads}) = (1-a)(1-b) = \frac{6}{12}\); \(P(\text{1 head}) = a(1-b)+(1-a)b = \frac{5}{12}\); \(P(\text{2 heads}) = ab = \frac{1}{12}\); giving \(\left(a+b = \frac{7}{12},\ ab = \frac{1}{12}\right)\)M1 Obtain two correct equations and attempt to solve
\(a = \frac{1}{3}\) \(\left(b = \frac{1}{4}\right)\)A1 Correct value for \(a\)
Question 3(b):
AnswerMarks Guidance
AnswerMarks Guidance
\(G_Y(t) = \left(\frac{6}{12} + \frac{5}{12}t + \frac{1}{12}t^2\right)^2\)M1 Square their \(G_X(t)\)
\(\frac{1}{144}\left(36 + 60t + 37t^2 + 10t^3 + t^4\right)\)M1 Obtain quartic polynomial from 3-term \(G_X(t)\)
A1
Question 3(c):
AnswerMarks Guidance
AnswerMarks Guidance
\(G_Y'(t) = \frac{1}{144}\left(60 + 74t + 30t^2 + 4t^3\right)\); \(G_Y''(t) = \frac{1}{144}\left(74 + 60t + 12t^2\right)\)M1 Differentiate their \(G_Y(t)\) twice
\(\text{Var}(Y) = G_Y''(1) + G_Y'(1) - (G_Y'(1))^2\); \(\frac{1}{144}(146) + \frac{7}{6} - \frac{49}{36} = \frac{59}{72} = 0.819\)M1 Use correct formula and attempt at \(\text{Var}(Y)\)
\(0.819\)A1
## Question 3(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $G_X(t) = \frac{6}{12} + \frac{5}{12}t + \frac{1}{12}t^2$; $P(\text{0 heads}) = (1-a)(1-b) = \frac{6}{12}$; $P(\text{1 head}) = a(1-b)+(1-a)b = \frac{5}{12}$; $P(\text{2 heads}) = ab = \frac{1}{12}$; giving $\left(a+b = \frac{7}{12},\ ab = \frac{1}{12}\right)$ | M1 | Obtain two correct equations and attempt to solve |
| $a = \frac{1}{3}$ $\left(b = \frac{1}{4}\right)$ | A1 | Correct value for $a$ |

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## Question 3(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $G_Y(t) = \left(\frac{6}{12} + \frac{5}{12}t + \frac{1}{12}t^2\right)^2$ | M1 | Square their $G_X(t)$ |
| $\frac{1}{144}\left(36 + 60t + 37t^2 + 10t^3 + t^4\right)$ | M1 | Obtain quartic polynomial from 3-term $G_X(t)$ |
| | A1 | |

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## Question 3(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $G_Y'(t) = \frac{1}{144}\left(60 + 74t + 30t^2 + 4t^3\right)$; $G_Y''(t) = \frac{1}{144}\left(74 + 60t + 12t^2\right)$ | M1 | Differentiate their $G_Y(t)$ twice |
| $\text{Var}(Y) = G_Y''(1) + G_Y'(1) - (G_Y'(1))^2$; $\frac{1}{144}(146) + \frac{7}{6} - \frac{49}{36} = \frac{59}{72} = 0.819$ | M1 | Use correct formula and attempt at $\text{Var}(Y)$ |
| $0.819$ | A1 | |

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3 George throws two coins, $A$ and $B$, at the same time. Coin $A$ is biased so that the probability of obtaining a head is $a$. Coin $B$ is biased so that the probability of obtaining a head is $b$, where $\mathrm { b } < \mathrm { a }$. The probability generating function of $X$, the number of heads obtained by George, is $\mathrm { G } _ { \mathrm { X } } ( \mathrm { t } )$. The coefficients of $t$ and $t ^ { 2 }$ in $\mathrm { G } _ { \mathrm { X } } ( \mathrm { t } )$ are $\frac { 5 } { 12 }$ and $\frac { 1 } { 12 }$ respectively.
\begin{enumerate}[label=(\alph*)]
\item Find the value of $a$.\\

The random variable $Y$ is the sum of two independent observations of $X$.
\item Find the probability generating function of $Y$, giving your answer as a polynomial in $t$.
\item Find $\operatorname { Var } ( Y )$.
\end{enumerate}

\hfill \mbox{\textit{CAIE Further Paper 4 2022 Q3 [8]}}