| Exam Board | CAIE |
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| Module | P1 (Pure Mathematics 1) |
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| Year | 2002 |
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| Session | November |
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| Topic | Trig Equations |
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5
- Show that the equation \(3 \tan \theta = 2 \cos \theta\) can be expressed as
$$2 \sin ^ { 2 } \theta + 3 \sin \theta - 2 = 0$$
- Hence solve the equation \(3 \tan \theta = 2 \cos \theta\), for \(0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }\).