CAIE S2 2019 November — Question 2 6 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2019
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPoisson distribution
TypeSingle period normal approximation - scaled period (normal approximation only)
DifficultyStandard +0.3 Part (i) is a straightforward Poisson probability calculation with λ=4.8. Part (ii) requires recognizing when to use normal approximation (large λ=144) and applying continuity correction, which is standard S2 material but slightly above routine recall due to the approximation step and time conversion.
Spec2.04d Normal approximation to binomial5.02i Poisson distribution: random events model5.02j Poisson formula: P(X=x) = e^(-lambda)*lambda^x/x!5.02k Calculate Poisson probabilities

2 Cars arrive at a filling station randomly and at a constant average rate of 2.4 cars per minute.
  1. Calculate the probability that fewer than 4 cars arrive in a 2 -minute period.
  2. Use a suitable approximating distribution to calculate the probability that at least 140 cars arrive in a 1-hour period.

Question 2:
Part (i):
AnswerMarks Guidance
AnswerMarks Guidance
\((\lambda = 2 \times 2.4) = 4.8\)M1 Any \(\lambda\)
\(e^{-4.8}\left(1 + 4 + \frac{4.8^2}{2} + \frac{4.8^3}{3!}\right)\)
\(0.294\) (3 sf)A1
2
Part (ii):
AnswerMarks Guidance
AnswerMarks Guidance
\((\lambda = 60 \times 2.4) = 144\), \(N('144', '144')\)M1 N and \(\sigma^2 = \mu\) SOI
\(\frac{139.5 - '144'}{\sqrt{'144'}} (= -0.375)\)M1 Allow with no continuity correction
\(\phi('0.375')\)M1 Correct area consistent with their working
\(0.646\) (3 sf)A1
4
**Question 2:**

**Part (i):**
| Answer | Marks | Guidance |
|--------|-------|----------|
| $(\lambda = 2 \times 2.4) = 4.8$ | M1 | Any $\lambda$ |
| $e^{-4.8}\left(1 + 4 + \frac{4.8^2}{2} + \frac{4.8^3}{3!}\right)$ | | |
| $0.294$ (3 sf) | A1 | |
| | **2** | |

**Part (ii):**
| Answer | Marks | Guidance |
|--------|-------|----------|
| $(\lambda = 60 \times 2.4) = 144$, $N('144', '144')$ | M1 | N and $\sigma^2 = \mu$ SOI |
| $\frac{139.5 - '144'}{\sqrt{'144'}} (= -0.375)$ | M1 | Allow with no continuity correction |
| $\phi('0.375')$ | M1 | Correct area consistent with their working |
| $0.646$ (3 sf) | A1 | |
| | **4** | |

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2 Cars arrive at a filling station randomly and at a constant average rate of 2.4 cars per minute.\\
(i) Calculate the probability that fewer than 4 cars arrive in a 2 -minute period.\\

(ii) Use a suitable approximating distribution to calculate the probability that at least 140 cars arrive in a 1-hour period.\\

\hfill \mbox{\textit{CAIE S2 2019 Q2 [6]}}