CAIE S2 2018 June — Question 5 9 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2018
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicContinuous Probability Distributions and Random Variables
TypePDF with multiple constants
DifficultyStandard +0.3 This is a standard S2 PDF question requiring integration to find constants using the total probability condition, then finding the equation of a linear function, and finally using the expectation formula. All steps are routine applications of well-practiced techniques with no novel problem-solving required, making it slightly easier than average.
Spec5.03a Continuous random variables: pdf and cdf5.03b Solve problems: using pdf5.03c Calculate mean/variance: by integration

5 \includegraphics[max width=\textwidth, alt={}, center]{b054d0a0-01b6-4785-807c-851551b90544-06_382_743_260_699} The diagram shows the probability density function, f , of a random variable \(X\), in terms of the constants \(a\) and \(b\).
  1. Find \(b\) in terms of \(a\).
  2. Show that \(\mathrm { f } ( x ) = \frac { 2 } { a } - \frac { 2 } { a ^ { 2 } } x\).
  3. Given that \(\mathrm { E } ( X ) = 0.5\), find \(a\).

Question 5(i):
AnswerMarks Guidance
\(\frac{1}{2} \times a \times b = 1\)M1 Attempt \(\Delta\) area \(= 1\) or \(\int(b - bx/a)\,dx = 1\) with correct limits
\(b = \frac{2}{a}\)A1
Question 5(ii):
AnswerMarks Guidance
\(\text{grad} = -\frac{2}{a^2}\) or \(-\frac{b}{a}\)B1 Allow without '\(-\)' sign (could be implied or seen in (i))
\(y - \left(\frac{2}{a}\right) = \text{grad} \times x\) or \(y = \text{grad} \times (x-a)\)M1 Correct use of \(y = mx + c\) or \(y - y_1 = m(x-x_1)\) with \((0,b)\) or \((a,0)\) including attempt at substitution of their \(b\)
\(y - \left(\frac{2}{a}\right) = -\frac{2}{a^2}x\) or \(y = -\frac{2}{a^2}(x-a)\) and \(y = \frac{2}{a} - \frac{2}{a^2}x\)A1 No errors seen
Question 5(iii):
AnswerMarks Guidance
\(\int_0^a \left(\frac{2}{a}x - \frac{2}{a^2}x^2\right)dx\)M1 Attempt int \(xf(x)\) ignore limits
\(= \left[\frac{1}{a}x^2 - \frac{2}{3a^2}x^3\right]_0^a\)A1 Correct integration ignore limits
\(a - \frac{2}{3}a = 0.5\)M1 Sub correct limits into their integral and \(= 0.5\)
\(a = 1.5\)A1
## Question 5(i):

| $\frac{1}{2} \times a \times b = 1$ | M1 | Attempt $\Delta$ area $= 1$ or $\int(b - bx/a)\,dx = 1$ with correct limits |
| $b = \frac{2}{a}$ | A1 | |

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## Question 5(ii):

| $\text{grad} = -\frac{2}{a^2}$ or $-\frac{b}{a}$ | B1 | Allow without '$-$' sign (could be implied or seen in (i)) |
| $y - \left(\frac{2}{a}\right) = \text{grad} \times x$ or $y = \text{grad} \times (x-a)$ | M1 | Correct use of $y = mx + c$ or $y - y_1 = m(x-x_1)$ with $(0,b)$ or $(a,0)$ including attempt at substitution of their $b$ |
| $y - \left(\frac{2}{a}\right) = -\frac{2}{a^2}x$ or $y = -\frac{2}{a^2}(x-a)$ and $y = \frac{2}{a} - \frac{2}{a^2}x$ | A1 | No errors seen |

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## Question 5(iii):

| $\int_0^a \left(\frac{2}{a}x - \frac{2}{a^2}x^2\right)dx$ | M1 | Attempt int $xf(x)$ ignore limits |
| $= \left[\frac{1}{a}x^2 - \frac{2}{3a^2}x^3\right]_0^a$ | A1 | Correct integration ignore limits |
| $a - \frac{2}{3}a = 0.5$ | M1 | Sub correct limits into their integral and $= 0.5$ |
| $a = 1.5$ | A1 | |

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5\\
\includegraphics[max width=\textwidth, alt={}, center]{b054d0a0-01b6-4785-807c-851551b90544-06_382_743_260_699}

The diagram shows the probability density function, f , of a random variable $X$, in terms of the constants $a$ and $b$.\\
(i) Find $b$ in terms of $a$.\\

(ii) Show that $\mathrm { f } ( x ) = \frac { 2 } { a } - \frac { 2 } { a ^ { 2 } } x$.\\

(iii) Given that $\mathrm { E } ( X ) = 0.5$, find $a$.\\

\hfill \mbox{\textit{CAIE S2 2018 Q5 [9]}}