CAIE S2 2018 June — Question 1 3 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2018
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMeasures of Location and Spread
TypeStandard unbiased estimates calculation
DifficultyEasy -1.2 This is a straightforward application of standard formulas for unbiased estimates of mean (x̄ = Σx/n) and variance (s² = [Σx² - (Σx)²/n]/(n-1)). It requires only direct substitution into memorized formulas with no problem-solving, conceptual understanding, or multi-step reasoning—purely mechanical calculation that is easier than a typical A-level question.
Spec5.05b Unbiased estimates: of population mean and variance

1 A random sample of 75 values of a variable \(X\) gave the following results. $$n = 75 \quad \Sigma x = 153.2 \quad \Sigma x ^ { 2 } = 340.24$$ Find unbiased estimates for the population mean and variance of \(X\).

Question 1:
AnswerMarks Guidance
AnswerMarks Guidance
\(\text{est}(\mu) = 153.2 \div 75 = 2.04\) (3 sf)B1
\(\text{est}(\sigma^2) = \frac{75}{74}\left(\frac{340.24}{75} - "2.04267"^2\right)\) oeM1
\(= 0.369\) (3 sf)A1 Accept 0.368
**Question 1:**

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\text{est}(\mu) = 153.2 \div 75 = 2.04$ (3 sf) | B1 | |
| $\text{est}(\sigma^2) = \frac{75}{74}\left(\frac{340.24}{75} - "2.04267"^2\right)$ oe | M1 | |
| $= 0.369$ (3 sf) | A1 | Accept 0.368 |

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1 A random sample of 75 values of a variable $X$ gave the following results.

$$n = 75 \quad \Sigma x = 153.2 \quad \Sigma x ^ { 2 } = 340.24$$

Find unbiased estimates for the population mean and variance of $X$.\\

\hfill \mbox{\textit{CAIE S2 2018 Q1 [3]}}