CAIE S2 2013 June — Question 1 5 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2013
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscrete Random Variables
TypeLinear combinations of independent variables
DifficultyModerate -0.8 This question tests straightforward application of standard results for linear combinations of independent random variables (variance of sum, variance of linear transformation). All parts require direct formula application with no problem-solving or conceptual insight—purely mechanical calculation of Var(S) = 3×3.1, Var(T) = 9×3.1, and combining these for S-T.
Spec5.04a Linear combinations: E(aX+bY), Var(aX+bY)

1 The mean and variance of the random variable \(X\) are 5.8 and 3.1 respectively. The random variable \(S\) is the sum of three independent values of \(X\). The independent random variable \(T\) is defined by \(T = 3 X + 2\).
  1. Find the variance of \(S\).
  2. Find the variance of \(T\).
  3. Find the mean and variance of \(S - T\).

Question 1:
AnswerMarks Guidance
(i)\(9.3\) B1 [1]
(ii)\(27.9\) B1 [1]
(iii)\(E(S) = 17.4\), \(E(T) = 19.4\); \(E(S-T) = -2.0\); \(\text{Var}(S-T) = 37.2\) M1, A1, B1ft [3]
## Question 1:

**(i)** | $9.3$ | B1 [1] |

**(ii)** | $27.9$ | B1 [1] |

**(iii)** | $E(S) = 17.4$, $E(T) = 19.4$; $E(S-T) = -2.0$; $\text{Var}(S-T) = 37.2$ | M1, A1, B1ft [3] | For subtracting $E[S]-E[T]$, can be non-numerical; ft (i) & (ii) adding (i) and (ii) ft non-negative answers only

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1 The mean and variance of the random variable $X$ are 5.8 and 3.1 respectively. The random variable $S$ is the sum of three independent values of $X$. The independent random variable $T$ is defined by $T = 3 X + 2$.\\
(i) Find the variance of $S$.\\
(ii) Find the variance of $T$.\\
(iii) Find the mean and variance of $S - T$.

\hfill \mbox{\textit{CAIE S2 2013 Q1 [5]}}