CAIE S2 2005 June — Question 1 4 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2005
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear combinations of normal random variables
TypeLinear transformation to achieve target parameters
DifficultyModerate -0.8 This is a straightforward application of linear transformation properties for mean and standard deviation. Students need only recall that E(aX+b) = aE(X)+b and SD(aX+b) = |a|SD(X), then solve two simple equations. It requires basic algebraic manipulation with no conceptual difficulty or problem-solving insight.
Spec5.02c Linear coding: effects on mean and variance

1 Exam marks, \(X\), have mean 70 and standard deviation 8.7. The marks need to be scaled using the formula \(Y = a X + b\) so that the scaled marks, \(Y\), have mean 55 and standard deviation 6.96. Find the values of \(a\) and \(b\).

AnswerMarks Guidance
\(55 = 70a + b\)M1 For an equation relating to the means
\(6.96 = 8.7a\) or \(6.96^2 = 8.7^2 a^2\)M1 For an equation relating to the variance or sd, only \(a\) in it
\(a = 0.8\)A1 For correct \(a\)
\(b = -1\)A1 (4) For correct \(b\)
$55 = 70a + b$ | M1 | For an equation relating to the means
$6.96 = 8.7a$ or $6.96^2 = 8.7^2 a^2$ | M1 | For an equation relating to the variance or sd, only $a$ in it
$a = 0.8$ | A1 | For correct $a$
$b = -1$ | A1 (4) | For correct $b$
1 Exam marks, $X$, have mean 70 and standard deviation 8.7. The marks need to be scaled using the formula $Y = a X + b$ so that the scaled marks, $Y$, have mean 55 and standard deviation 6.96. Find the values of $a$ and $b$.

\hfill \mbox{\textit{CAIE S2 2005 Q1 [4]}}